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Alecsey [184]
3 years ago
10

Negative 8/9 divided by 2/3

Mathematics
1 answer:
djverab [1.8K]3 years ago
7 0

Answer:

\frac{4}{3}

Step-by-step explanation:

<u>Step 1:  Divide</u>

<u />\frac{8}{9} / \frac{2}{3}

\frac{8}{9} * \frac{3}{2}

\frac{8 * 3}{9 * 2}

\frac{24/6}{18/6}

\frac{4}{3}

Answer:  \frac{4}{3}

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What is 110% of 90 as a fraction
Vlad1618 [11]
110% of 90 is:
90*1.10 = 99

5 0
3 years ago
Read 2 more answers
An umbrella sprinkler is positioned on a ceiling at a point whose x- coordinate is 0. Negative values of a indicate distances, i
vodka [1.7K]

Answer:

-1/4x² + 3

Step-by-step explanation:

Given that:

Path of sprinkler is modeled by the quadratic function :

w(x) = -1/4(x^2 -12 )

w(x) = height of the water, in meters, at position x

The height of ceiling as a constant or Coefficient = w(x)

Expanding w(x)

-1/4(x^2 -12 )

-1/4 * x² + 1/4 * 12

-1/4x² + 3

The height of ceiling is -1/4x² + 3

8 0
3 years ago
Consider the following equation of the form dy/dt = f(y)dy/dt = ey − 1, −[infinity] &lt; y0 &lt; [infinity](a) Sketch the graph
kotegsom [21]

Complete Question:

The complete question is shown on the first uploaded image

Answer:

a) The graph of  f(y) versus y. is shown on the second uploaded image

b) The critical point is at y = 0  and the solution is asymptotically unstable.

c)The phase line is shown on the third uploaded image

d) The sketch for the several graphs of solution in the ty-plane  is shown on the fourth uploaded image

Step-by-step explanation:

Step One: Sketch The Graph of  f(y) versus y

Looking at the given differential equation

       \frac{dy}{dt} = e^{y} - 1 for -∞ < y_{o} < ∞

 We can say let \frac{dy}{dt} = f(y) =e^{y} - 1

Now the dependent value is f(y) and the independent value is y so to sketch is graph we can assume a scale in this case i cm on the graph is equal to 2 unit for both f(y) and y and the match the coordinates and after that join the point to form the graph as shown on the uploaded image.

Step Two : Determine the critical point

   To fin the critical point we have to set   \frac{dy}{dt} = 0

       This means e^{y} - 1 = 0

                          For this to be possible e^{y} = 1

                          which means that  e^{y} = e^{0}

                          which implies that y = 0

Hence the critical point occurs at y = 0

meaning that the equilibrium solution is y = 0

As t → ∞, our curve is going to move away from y = 0  hence it is asymptotically unstable.

Step Three : Draw the Phase lines

A phase line can be defined as an image that shows or represents the way an ODE(ordinary differential equation ) that does not explicitly depend on the independent variable behaves in a single variable. To draw this phase line , draw the y-axis as a vertical line and mark on it the equilibrium, i.e. where  f(y) = 0.

In each of the intervals bounded  by the equilibrium draw an upward

pointing arrow if f(y) > 0 and a downward pointing arrow if f(y) < 0.

      This phase line would solely depend on y does not matter what t is

On the positive x axis it would get steeper very quickly as you move up (looking at the part A graph).

For  below the x-axis which stable (looking at the part a graph) we are still going to have negative slope but they are going to be close to 0 and they would take a little bit longer to get steeper  

Step Four : Draw a Solution Curve

A solution curve is a curve that shows the solution of a DE (deferential equation)

Here the solution curve would be drawn on the ty-plane

So the t-axis(x-axis) is its the equilibrium  that is it is the solution

If we are above the x-axis it is going to increase faster and if we are below it is going to decrease but it would be slower (looking at part A graph)

5 0
3 years ago
Find the product <br> -1/2y(2y^3-8)
blondinia [14]

Answer:

-y^4+4y

Step-by-step explanation:

3 0
3 years ago
If a = -8, b = -7, c = 6, then verify that (a+b) + c = a+ (b+c)<br><br> tysm for de help ✨
NISA [10]

The given information is,

→ a = -8

→ b = -7

→ c = 6

Let's verify the problem,

→ (a+b) + c = a+ (b+c)

→ (-8 - 7) + 6 = -8 + (-7 + 6)

→ -15 + 6 = -8 - 1

→ -9 = -9

→ [ LHS = RHS ]

Hence, it is equal and verified.

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