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3 years ago

evan graphs the function h(x)=x^2+4. Victor graphs the function g(x)=(x+4)^2. Which statements are true regarding the two graphs

Mathematics

1 answer:

vovangra [49]3 years ago

5 0

Can you please add the statements? ThankS!

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An outside thermometer reads -5 degrees at 8:00 a.m. By 12:30 p.m. the temperature outside has increased by 11 degrees. At 12:30

Lesechka [4]

Answer:

73 degrees.

Step-by-step explanation:

So, let's see the information provided in the question.

At 8 AM, the thermometer was reading -5 degrees.

At 12:30 PM, the temperature has increased by 11 degrees, so it's now +6 degrees outside.

Inside Susan's house, the temperature is 7 degrees more than 11 times the outside temperature, at 12:30 PM.

So, we know the outside temperature at 12:30 PM is +6 degrees.

11 times 6 = 66 degrees.

Then we add the additional 7 degrees, to get a total of 73 degrees.

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3 years ago

PLS HELP ASAP

slega [8]

Answer:

rn or later?

Step-by-step explanation:

6 0

3 years ago

Evaluate the expression when b=2 12-b

exis [7]

Answer:

10 $\huge\checkmark$

Step-by-step explanation:

Hi there, hope you are having a nice day!

All we should do is plug in the value of b:

12-2

10 (Answer)

Hope you find it helpful.

Feel free to ask if you have any questions.

$\bf{-MistySparkles^**^*$

7 0

3 years ago

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Find the exponential function that passes through the points (2,80) and (5,5120)

juin [17]

Answer:

y = 5·4^x

Step-by-step explanation:

If you have two points, (x1, y1) and (x2, y2), whose relationship can be described by the exponential function ...

y = a·b^x

you can find the values of 'a' and 'b' as follows.

Substitute the given points:

y1 = a·b^(x1)

y2 = a·b^(x1)

Divide the second equation by the first:

y2/y1 = ((ab^(x2))/(ab^(x1)) = b^(x2 -x1)

Take the inverse power (root):

(y2/y1)^(1/(x2 -x1) = b

Use this value of 'b' to find 'a'. Here, we have solved the first equation for 'a'.

a = y1/(b^(x1))

In summary:

b = (y2/y1)^(1/(x2 -x1))
a = y1·b^(-x1)

For the problem at hand, (x1, y1) = (2, 80) and (x2, y2) = (5, 5120).

b = (5120/80)^(1/(5-2)) = ∛64 = 4

a = 80·4^(-2) = 80/16 = 5

The exponential function is ...

y = 5·4^x

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3 years ago

Given a segment with endpoints A and B, What figure can you construct using the steps below?

RoseWind [281]

I believe the correct answer from the choices listed above is option A. Given a segment with endpoints A and B and the steps given above, the figure that you can construct would be a perpendicular bisector. The perpendicular bisector of a line segment can be constructed using a compass by drawing circles centered at and with radius and connecting their two intersections.

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3 years ago

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