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GalinKa [24]
4 years ago
7

When a 12.0-V battery causes 2.00 μC of charge to flow onto the plates of an air-filled capacitor, how much work did the battery

do?
Physics
2 answers:
Mrac [35]4 years ago
7 0

Answer:

Explanation:

Voltage, V = 12 V

Charge, q = 2 micro coulomb = 2 x 10^-6 C

Work = energy

W = 0.5 x q x V

W = 0.5 x 2 x 10^-6 x 12

W = 12 x 10^-6 J

IRINA_888 [86]4 years ago
5 0

Answer:

2.4*10⁻⁵ J

Explanation:

workdone in moving a charge across a potential difference = charge * the potential difference across.

w = qV

q = 2.0μC = 2.0*10⁻⁶C

V = 12.0V

W = 2.0*10⁻⁶ * 12.0

W = 2.4*10⁻⁵ J

The battery did a work of 2.4*10⁻⁵ J

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3 years ago
A nickel (5 cent coin) has a mass of 5.0 g. How many nickels are there in a stack of nickels with a mass of 10.0 kg?
Marrrta [24]

Answer:

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Explanation:

One way to solve proportionality problems, direct and inverse: the simple 3 rule.

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