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2 years ago

List 4 ways to separate mixtures

1 answer:

7 0

1.Paper Chromatography. This method is often used in the food industry. ...

2.Filtration. This is a more common method of separating an insoluble solid from a liquid. ...

3.Evaporation. ...

4Simple distillation. ...
Fractional distillation.

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A box sliding on a horizontal frictionless surface encounters a spring attached to a rigid wall and compresses the spring by a c

GaryK [48]

Answer:

a) K = 49.5 J b) k = 1378 N / m c) ΔE = 34 J d) μ = 0.399

Explanation:

For this exercise we will use the concepts of energy

a) The initial kinetic energy is

K = ½ m v²

K = ½ 3.96 5²

K = 49.5 J

b) let's use energy conservation

Em₀ = K = ½ m v²

$Em_{f}$ = Ke = ½ k x²

Em₀ = $Em_{f}$

½ m v² = ½ k x²

k = m v² / x²

k = 3.96 5² / 0.268²

k = 1378 N / m

c) Let's calculate the final energy of the spring

$Em_{f}$ = Ke = ½ k x²

$Em_{f}$ = ½ 1378 0.15²

$Em_{f}$ = 15.5 J

The initial energy is the kinetics of the block

Em₀ = 49.5 J

The lost energy is the difference with the initial

ΔE = $Em_{f}$ - Em₀

ΔE = 15.5 - 49.5

ΔE = - 34 J

the negative sign means that the energy dissipates

d) For this part we use the concept of work

W = F d cos θ = ΔK

In this case the force is the friction force that always opposes displacement, so the angle 180 ° and cos 180 = -1

W = -fr d = ΔK

The force of friction is

fr = μ N

With Newton's second law

N-w = 0

N = W = mg

Let's calculate

-μ mg d = Kf -K₀o

μ = K₀ / mgd

μ = 49.5 / (3.96 9.8 3.20)

μ = 0.399

8 0

3 years ago

A satellite is orbiting the Earth in a circular orbit of radius r. Its frequency is independent of its height above the surface

Pie

Answer:

a. TRUE

Explanation:

When a satellite is launched to orbit around earth, it has to produce its own artificial gravity by performing rotations. The frequency of this rotation is given by the following formula:

f = √[ac/4πR²]

where,

f = frequency

ac = centripetal acceleration

R = Radius of the satellite

Therefore, it is clear from this formula that the frequency of rotation of the satellite is independent of its height above the surface of earth. So, the correct option is:

5 0

2 years ago

A cell phone weighing 80 grams is flying through the air at 15 m/s. What’s is it’s kinetic energy

zubka84 [21]

Answer:

The kinetic energy of the cell phone is 9J

Explanation:

The kinetic energy is the energy possessed by a body by virtue of motion.

The kinetic energy is expressed as

KE= 1/2m(v)²

Given data

Mass of cell phone m= 80g--to kg=80/1000= 0.08kg

Velocity of cell phone v= 15m/s

Substituting our given data we have

KE= 1/2*0.08(15)²

KE= (0.08*225)/2

KE=18/2

KE= 9J

6 0

2 years ago

An experiment measures the growth of crystals in a liquid solution aboard the space shuttle. A collection of bottles has the liq

Fantom [35]

the control would be A. the bottle with 0% concentration, because you're not changing anything.

7 0

2 years ago

Read 2 more answers

A man can jump 1.5 m on earth. calculate the approximate

Olegator [25]

Answer:

18 m

Explanation:

G = Gravitational constant

m = Mass of planet = $\rho V$

$\rho$ = Density of planet

V = Volume of planet assuming it is a sphere = $\dfrac{4}{3}\pi r^3$

r = Radius of planet

Acceleration due to gravity on a planet is given by

$g=\dfrac{Gm}{r^2}\\\Rightarrow g=\dfrac{G\rho V}{r^2}\\\Rightarrow g=\dfrac{G\rho \dfrac{4}{3}\pi r^3}{r^2}\\\Rightarrow g=\dfrac{4G\rho\pi r}{3}$

So,

$g\propto \rho r$

Density of other planet = $\rho_p=\dfrac{1}{4}\rho_e$

Radius of other planet = $r_p=\dfrac{1}{3}r_e$

$\dfrac{g_e}{g_p}=\dfrac{\rho_e r_e}{\rho_p r_p}\\\Rightarrow \dfrac{g_e}{g_p}=\dfrac{\rho_e r_e}{\dfrac{1}{4}\rho_e\times \dfrac{1}{3}r_e}\\\Rightarrow \dfrac{g_e}{g_p}=12\\\Rightarrow g_p=\dfrac{g_e}{12}\\\Rightarrow g_p=\dfrac{9.8}{12}$

Since the person is jumping up the acceleration due to gravity will be negative.

From kinematic equations we have

$v^2-u^2=2g_es\\\Rightarrow u^2=v^2-2g_es\\\Rightarrow u^2=0-2\times -9.8\times 1.5\\\Rightarrow u^2=2\times 9.8\times 1.5$

On the other planet

$v^2-u^2=2g_ps\\\Rightarrow s=\dfrac{v^2-u^2}{2g_p}\\\Rightarrow s=\dfrac{0-(2\times 9.8\times 1.5)}{2\times -\dfrac{9.8}{12}}\\\Rightarrow s=18\ \text{m}$

The man can jump a height of 18 m on the other planet.

5 0

2 years ago