Assuming it is on a horizontal surface:
friction = μR
R = 20g (g is gravity 9.81)
so Friction = 0.085 x 20g
Work done is force x distance
so Work done = 0.085 x 20g x 28
= 466.956 J
Answer:
h=20.38 m
Explanation:
Given that
Initial speed of object u = 20 m/s
Acceleration 
We know that

Here acceleration and velocity is in opposite direction so the object will come rest after reaching at distance h.When body will reach at its highest position then velocity will become zero(v=0).
Now by putting the values


h=20.38 m
Answer:
c. Include ancillary clinical and medical staff in the process
Explanation:
The best way to achieve goal i.e. improve clinical documentation to support the quality of care, data quality, and HIM coding accuracy will be to include the clinical and medical staff in the process since it will train them and motivate them which is the best approach to make everyone understand the importance of the program.
Answer:
Reproducibility of research
Explanation:
The principle of science that explains why similar experimental investigations conducted in different parts of the world could result in the same outcome is referred to as reproducibility.
<em>A good research or experiment in science must be reproducible, otherwise, the outcome of such an experiment might become inadmissible within the scientific community. It is a core principle of the scientific method that similar results should be obtained when an experiment or observational study conducted in one place is repeated in another place with the same procedure. Hence, an experiment must be reproducible in science in order for the outcome of such an experiment to be part of the general scientific knowledge. </em>
Answer:
3091.56
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s² (positive downward and negative upward)

Distance traveled in the first stage is 1093.75 m

Velocity at the end of first stage is 87.5 m/s

Acceleration of the second stage is 4.5 m/s²

Distance traveled in the second stage is 1100 m

Distance traveled after the second stage has stopped firing is 894.81 m
Total height the rocket reached = 1093.75+1100+897.81 = 3091.56 m