Question

A spherical conducting shell has an inner radius of 0.2 m and an outer radius of 0.4 m. There is no charge on the outer surface but the shell does have a nonzero net charge. All charges remain at rest. The potential at the outer surface is -2 V. The potential at the center of the cavity is g

Answer 1

Answer:

$P_c=-4v$

Explanation:

From the question we are told that:

Inner radius $r_1=0.2$

Outer radius$r_2=0.4$

Potential at the outer surface is $P_o= -2 V$

Generally the equation for Potential at the outer surface P_o  is mathematically given by

$P_o=\frac{KQ}{r_2}$

$-2=\frac{KQ}{0.4}$

Therefore

$KQ=-0.8v$

Generally the equation for Potential at Center of outer cavity $P_c$  is mathematically given by

$P_c=\frac{KQ}{r_1}$

$P_c=\frac{-0.8}{0.2}$

$P_c=-4v$

Therefore the potential at the center of cavity

$P_c=-4v$