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diamong [38]
4 years ago
7

Pyruvate kinase catalyzes the transfer of a phosphoryl group from phosphoenolpyruvate to ADP in the last step of glycolysis, for

ming pyruvate in the process. Vertebrates have several isozymes of pyruvate kinase, which can be allosterically inhibited by compounds including ATP and acetyl-CoA. What is an effect of cAMP-dependent protein kinase (PKA) inactivation of the liver isozyme but not the muscle isozyme?
A. Phosphate from the dephosphorylation of the liver isozyme is used to generate ATP and provide energy for movement.
B. Glycolysis is inhibited in the muscle, but not liver, when blood sugar is low.
C. Under stress (fight-or-flight) conditions, muscle can use glycolysis to break down glucose.
D. Glycogen synthesis is promoted in the liver as an energy store.
Chemistry
1 answer:
Degger [83]4 years ago
6 0

Answer:

The correct answer is under C under stress condition muscle can can use glycolysis to breakdown glucose.

Explanation:

Each and every metabolic process of our body remains under tight regulation by various compounds present inside our body.

   For example the catabolic process glycolysis is regulated by ATP,citrate,acetyl CoA etc.

     The cAMP dependent protein kinase inactivation of liver isozyme but not the muscle isozyme result in the occurrence of glycolysis in muscle during stress condition as gluconeogenesis cannot occur in muscle.

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Se hace reaccionar 4,00 g de aluminio y 42,00 g de bromo, según la reacción: Al(s)+Br2(l)⟶AlBr3(s) Calcular las moles de AlBr3(s
NeX [460]

Answer:

0.145 moles de AlBr3.

Explanation:

¡Hola!

En este caso, al considerar la reacción química dada:

Al(s)+Br2(l)⟶AlBr3(s)

Es claro que primero debemos balancearla como se muestra a continuación:

2Al(s)+3Br2(l)⟶2AlBr3(s)

Así, calculamos las moles del producto AlBr3 por medio de las masas de ambos reactivos, con el fin de decidir el resultado correcto:

n_{AlBr_3}^{por\ Al}=4.00gAl*\frac{1molAl}{27gAl} *\frac{2molAlBr_3}{2molAl}=0.145mol AlBr_3\\\\n_{AlBr_3}^{por\ Br_2}=42.00gr*\frac{1molr}{160g Br_2} *\frac{2molAlBr_3}{3molBr_2}=0.175mol AlBr_3

Así, inferimos que el valor correcto es 0.145 moles de AlBr3, dado que viene del reactivo límite que es el aluminio.

¡Saludos!

3 0
3 years ago
Coal containing 15.0% H2O, 2.0% S and 83.0% C by mass is burnt with the stoichiometric amount of air in a furnace. What is the m
devlian [24]

Answer:

This is a coal combustion process and we will assume

Inlet coal amount = 100kg

It means that there are

15kg of H2O, 2kg of Sulphur and 83kg of Carbon

Now to find the mole fraction of SO2(g) in the exhaust?

Molar mass of S = 32kg/kmol

Initial moles n  of S = 2/32 = 0.0625kmols

Reaction:  S + O₂ = SO₂

That is 1 mole of S reacts with 1 mole of O₂ to give 1 mole of SO₂

Then, it means for 0.0625 kmoles of S, we will have 0.0625 kmole of SO2 coming out of the exhaust

The mole fraction of SO2(g) in the exhaust=0.0625kmols

Explanation:

5 0
3 years ago
Which is the correct answer
Sholpan [36]

Answer:

In my opinion, I think its 2

Explanation:

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3 years ago
What energy is defined as the energy of motion
Veronika [31]

Answer:

I believe it is kinetic energy

Hope this is right .-.

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3 years ago
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mr_godi [17]
Convection is a form of heat transfer that occurs in fluids, which would include liquids and gases.
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