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MissTica
2 years ago
9

Friction is a ____________ force a. Artificial b. Natural c. Pessimistic d. Negative

Physics
2 answers:
Ivanshal [37]2 years ago
7 0

Friction is a natural force which exist

Daniel [21]2 years ago
5 0

Answer:

natural is the answer

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Energy Conservation Theory,

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7 0
1 year ago
Which phrase best describes sir isaac newton's contributions to modern science and therefore to the industrial revolution?
astraxan [27]
Can you please give the phrases? 

But, I'll help what I can.

First, he was the first to discover gravity. He was not bonked by the head by an apple, rather he watched an apple fall from a tree before he decided to explore gravity further. 

He was also the first scientist to be knighted, which is a great honor, as you can expect. 

Newton also developed The Three Laws of Motion. They are extremely important to physics and are considered some of the foundation for physics today. 

He also discovered calculus, which is complex math that is very helpful to scientists today. 

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2 years ago
Is work done in this example: A student lifting a heavy backpack off of the floor.
vagabundo [1.1K]
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2 years ago
Read 2 more answers
A boat of mass 250 kg is coasting, with its engine in neutral, through the water at speed 1.00 m/s when it starts to rain with i
Vera_Pavlovna [14]

Answer:

Explanation:

1. We use the conservation of momentum for before the raining and after. And also we take into account that in 0.5h the accumulated water is

100kg/h*0.5h = 50kg

p_{b}=p_{a}\\M_{b}v_{b}=(M_{b}+m_{r})v_{a}\\v_{a}=\frac{M_{b}v_{b}}{M_{b}+m_{r}}=\frac{250kg*1\frac{m}{s}}{250kg+50kg}=0.83\frac{m}{s}

2. the momentum does not conserve because the drag force of water makes that the boat loses velocity

3. If we assume that the force of the boat before the raining is

F=ma=m\frac{v-v_{0}}{t-t_{0}}=250kg\frac{1m}{s^{2}}=250N

where we have assumed that the acceleration of the boat is 1m/s{2} just before the rain starts

And if we take the net force as

F_{net}=M_{b}a_{net}=F-F_{d}=250N-bv^{2}\\F_{net}=250N-0.5N\frac{s^{2}}{m^{2}}(1\frac{m}{s})^{2}=249.5N\\a_{net}=\frac{249.5N}{M_{b}}=\frac{249.5N}{250kg}=0.99\frac{m}{s^{2}}

where we take v=1m/s because we are taking into account tha velocity just after the rain stars.

I hope this is useful for you

regards

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3 years ago
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Explanation:

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