<h2>Answer </h2>
<h3>1) iron </h3>
<h3>2) Aluminium </h3>
<h3>3) sliver </h3>
<h3>4) copper </h3>
I hope it's helpful for you ☺️
Answer:
190v I believe
hope this helped a little and if it did pls mark brainiest :)
24km/hour=(20/3)m/s
Hence, W=1/2*1168kg*[(20/3)/m/s]^2=25955.56J
The average force a 70.0 kg sprinter exerts backward on the track is 84 N.
<h3>
What is law of conservation of energy?</h3>
The law of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another.
E = Fd
where;
- F is the applied force
- d is the displacement of the object
The average force exerted by the sprinter is calculated as follows;
F = ma
where;
- a is the acceleration of the sprinter
- m is mass of the sprinter
The acceleration of the sprinter is calculated as follows;
v² = u² + 2as
where;
- v is the final velocity
- u is the initial velocity
- s is the distance
(8)² = (2)² + (2x25)a
64 = 4 + 50a
60 = 50a
a = 60/50
a = 1.2 m/s²
Average force exerted by the sprinter;
F = ma
F = 70 kg x 1.2 m/s²
F = 84 N
Learn more about average force here: brainly.com/question/16200276
#SPJ1
The final velocity of the Jet from the takeoff is 15.5 m/s.
<h3>
Final velocity of the Jet</h3>
The final velocity of the jet is determine by applying second kinematic equation, using the principle of average velocity as shown below.
s = (u + v)t/2
where;
- s is the distance traveled by the Jet
- u is the initial velocity of the jet
- v is the final velocity of the jet
- t is the time of motion
s = (0 + v)t/2
2s = vt
v = 2s/t
v = (2 x 9.3) /1.2
v = 15.5 m/s
Thus, the final velocity of the Jet from the takeoff is 15.5 m/s.
Learn more about final velocity here: brainly.com/question/25905661
