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frutty [35]
3 years ago
8

Explain why the pbcl2 dissolved when water was added

Chemistry
1 answer:
lara [203]3 years ago
4 0

PbCl2 would not dissolve because it is insoluble based on the solubility rules for substances that will dissolve in water. This compound would instead form a solid precipitate at the bottom of the container.

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How many electrons can the px atomic orbital subtype hold?
NemiM [27]
The p sublevel holds 6 electrons because it has 3 orbitals.
8 0
3 years ago
PLEASE HELP!!
wariber [46]

Answer:

answer is option 2 hope it helps

8 0
3 years ago
Lakshmi has a sample of ammonium nitrate (NH4NO3) that has a mass of 40. 10 g. She knows that the molar mass of NH4NO3 is 80. 04
nexus9112 [7]

Moles are an estimation of the smallest unit of the molecules and the atoms in a sample. The moles of ammonium nitrate in a sample are 0.5010 moles.

<h3>What are moles?</h3>

Moles are calculated by dividing the mass of the substance in gm by that of the molar mass in gram per mole.  

Given.

Mass of ammonium nitrate = 40.10 gm

The molar mass of ammonium nitrate = 80. 0432 g/mol

Moles of ammonium nitrate are calculated as:

\begin{aligned}\rm moles &= \rm \dfrac{mass}{molar\; mass}\\\\&= \dfrac{40.10}{80.0432}\\\\&= 0.5010 \;\rm mol\end{aligned}

Therefore, moles of ammonium nitrate present is option d. 0.5010 moles.

Learn more about moles here:

brainly.com/question/2396149

8 0
2 years ago
NH3 is a weak base (Kb = 1.8 × 10–5) and so the salt NH4Cl acts as a weak acid. What is the pH of a solution that is 0.084 M in
kolbaska11 [484]
Answer is: pH of solution is 5,17.
Kb(NH₃) = 1,8·10⁻⁵.
c(NH₄Cl) = 0,084 M = 0,084 mol/L.
Chemical reaction: NH₄⁺ + H₂O → NH₃ + H₃O⁺.
Ka · Kb = 10⁻¹⁴.
Ka(NH₄⁺) = 10⁻¹⁴ ÷ 1,8·10⁻⁵.
Ka(NH₄⁺) = 5,55·10⁻¹⁰.
[H₃O⁺] = [NH₃]  = x.
Ka(NH₄⁺) = [H₃O⁺] · [NH₃] ÷ [NH₄⁺].
5,55·10⁻¹⁰ = x² ÷ (0,084 M - x).
Solve quadratic equation: x = [H₃O⁺] = 6,8·10⁻⁶ M.
pH = -log[H₃O⁺].
pH = -log(6,8·10⁻⁶ M) = 5,17.
7 0
3 years ago
The change in entropy, Δ S ∘ rxn , is related to the the change in the number of moles of gas molecules, Δ n gas . Determine the
rewona [7]

Answer:

The entropy decreases.

Explanation:

The change in the standard entropy of a reaction (ΔS°rxn) is related to the change in the number of gaseous moles (Δngas), where

Δngas = n(gaseous products) - n(gaseous reactants)

  • If Δngas > 0, the entropy increases
  • If Δngas < 0, the entropy decreases.
  • If Δngas = 0, there is little or no change in the entropy.

Let's consider the following reaction.

2 H₂(g) + O₂(g) ⟶ 2 H₂O(l)

Δngas = 0 - 3 = -3, so the entropy decreases.

8 0
3 years ago
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