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4 years ago

Explain why the pbcl2 dissolved when water was added

1 answer:

4 0

PbCl2 would not dissolve because it is insoluble based on the solubility rules for substances that will dissolve in water. This compound would instead form a solid precipitate at the bottom of the container.

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What is the fuel used in a fuel-cell automobile

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Hydrogen gas

Explanation

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3 years ago

Write the balanced equation for the formation of carbon dioxide.

ohaa [14]

C + O2 ——> CO2
Carbon plus oxygen forms carbon dioxide

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3 years ago

1. What does the -ite or -ate ending in a polyatomic ion mean?

den301095 [7]

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3 years ago

How many possible Mole Ratios are in the following reaction:<br> ZnO + 2 HCl --> ZnCl2 + H2O

Misha Larkins [42]

Answer: 2 moles

Explanation:

5 0

3 years ago

The reaction of NH3 and O2 forms NO and water. The NO can be used to convert P4 to P4O6, forming N2 in the process. The P4O6 can

posledela

Answer : The mass of $PH_3$ produced from the reaction is, 0.651 grams.

Explanation :

The chemical reactions used are:

(1) $4NH_3+5O_2\rightarrow 4NO+6H_2O$

(2) $6NO+P_4\rightarrow P_4O_6+3N_2$

(3) $P_4O_6+6H_2O\rightarrow 4H_3PO_4$

(4) $4H_3PO_4\rightarrow PH_3+3H_3PO_4$

First we have to calculate the moles of $NH_3$

$\text{Moles of }NH_3=\frac{\text{Mass of }NH_3}{\text{Molar mass of }NH_3}$

Molar mass of $NH_3$ = 17 g/mol

$\text{Moles of }NH_3=\frac{1.95g}{17g/mol}=0.115mol$

Now we have to calculate the moles of $NO$

From the balanced chemical reaction 1, we conclude that:

As, 4 moles of $NH_3$ react to give 4 moles of $NO$

So, 0.115 moles of $NH_3$ react to give 0.115 moles of $NO$

Now we have to calculate the moles of $P_4O_6$

From the balanced chemical reaction 2, we conclude that:

As, 6 moles of $NO$ react to give 1 moles of $P_4O_6$

So, 0.115 moles of $NO$ react to give $\frac{0.115}{6}=0.0192$ moles of $P_4O_6$

Now we have to calculate the moles of $H_3PO_4$

From the balanced chemical reaction 3, we conclude that:

As, 1 moles of $P_4O_6$ react to give 4 moles of $H_3PO_4$

So, 0.0192 moles of $P_4O_6$ react to give $0.0192\times 4=0.0768$ moles of $H_3PO_4$

Now we have to calculate the moles of $PH_3$

From the balanced chemical reaction 4, we conclude that:

As, 4 moles of $H_3PO_4$ react to give 1 moles of $PH_3$

So, 0.0768 moles of $H_3PO_4$ react to give $\frac{0.0768}{4}=0.0192$ moles of $PH_3$

Now we have to calculate the mass of $PH_3$

$\text{ Mass of }PH_3=\text{ Moles of }PH_3\times \text{ Molar mass of }PH_3$

Molar mass of $PH_3$ = 33.9 g/mole

$\text{ Mass of }PH_3=(0.0192moles)\times (33.9g/mole)=0.651g$

Therefore, the mass of $PH_3$ produced from the reaction is, 0.651 grams.

6 0

3 years ago