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3 years ago

Over-encouraging lesser skilled players can lead to embarrassment. a. True b. False

Chemistry

2 answers:

Alex Ar [27]3 years ago

7 0

Answer: Option (a) is correct.

Explanation:

A person with less skills needs to work more or practice more on his abilities in order to improve their athletic ability to build a stronger team.

Over encouragement to lesser skilled person can lead to the development of over confidence. As after over encouragement, the less skilled person can have the illusion of knowing each and everything which is not true for anyone.

As no one is perfect, therefore, over-encouraging lesser skilled players can lead to embarrassment.

Margarita [4]3 years ago

6 0

My answer would be a. True

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3 years ago

Solid NaBr is slowly added to a solution that is 0.073 M in Cu+ and 0.073 M in Ag+.Which compound will begin to precipitate firs

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Answer :

AgBr should precipitate first.

The concentration of $Ag^+$ when CuBr just begins to precipitate is, $1.34\times 10^{-6}M$

Percent of $Ag^+$ remains is, 0.0018 %

Explanation :

$K_{sp}$ for CuBr is $4.2\times 10^{-8}$

$K_{sp}$ for AgBr is $7.7\times 10^{-13}$

As we know that these two salts would both dissociate in the same way. So, we can say that as the Ksp value of AgBr has a smaller than CuBr then AgBr should precipitate first.

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$CuBr\rightleftharpoons Cu^++Br^-$

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$K_{sp}=[Cu^+][Br^-]$

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Now we have to calculate the concentration of silver ion.

The solubility equilibrium reaction will be:

$AgBr\rightleftharpoons Ag^++Br^-$

The expression for solubility constant for this reaction will be,

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$7.7\times 10^{-13}=[Ag^+]\times 5.75\times 10^{-7}M$

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Percent of $Ag^+$ remains = $\frac{1.34\times 10^{-6}}{0.073}\times 100$

Percent of $Ag^+$ remains = 0.0018 %

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