Answer:
270 m
Explanation:
Given:
v₀ = 63 m/s
a = 2.8 m/s²
t = 4.0 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (63 m/s) (4.0 s) + ½ (2.8 m/s²) (4.0 s)²
Δx = 274.4 m
Rounded to two significant figures, the displacement is 270 meters.
Answer:
Explanation:
The PE equation for a mass/spring system is
Δx² and filling in:
and
so
k = 26000 N/m
If the displacement from equilibrium changes more, the PE needed to compress it will also change.
gives us that
PE = 520J
Answer:
Acceleration of the box is 4.9 m/s².
Explanation:
The free body diagram is shown below.
The weight of the body can be resolved into two mutually perpendicular components as shown. The force responsible for sliding motion of the box along the incline is due to
acting along the incline.
Therefore, as per Newton's second law of motion,
Net force = ![mass\times acceleration](https://tex.z-dn.net/?f=mass%5Ctimes%20acceleration)
Now, net force acting along the incline is only ![mg\sin \theta](https://tex.z-dn.net/?f=mg%5Csin%20%5Ctheta)
Therefore,
![mg\sin \theta=ma\\a=g\sin \theta](https://tex.z-dn.net/?f=mg%5Csin%20%5Ctheta%3Dma%5C%5Ca%3Dg%5Csin%20%5Ctheta)
Now, ![g=9.8\textrm{ and } \theta = 30](https://tex.z-dn.net/?f=g%3D9.8%5Ctextrm%7B%20and%20%7D%20%5Ctheta%20%3D%2030)
Therefore, the acceleration of the box is given as:
![a=9.8\times \sin(30)=9.8\times 0.5=4.9\textrm{ }m/s^{2}](https://tex.z-dn.net/?f=a%3D9.8%5Ctimes%20%5Csin%2830%29%3D9.8%5Ctimes%200.5%3D4.9%5Ctextrm%7B%20%7Dm%2Fs%5E%7B2%7D)
Acceleration of the box is 4.9 m/s².
Answer:
<em><u>A.9</u></em><em><u> </u></em><em><u>kWh</u></em>
Explanation:
Tv is rated 0.1 kW
in one day energy used will be 0.1kW ×3hr=0.3kwh
in 30 days energy used will be 0.3kwh×30=9kwh
Answer: You may hurt yourself or fail
Explanation: If you do not follow the steps right you might end up only hurting yourself or embarrising youself in front of others. You don't want to fail and then you just keep doing it over and over.
Hope this helps^^