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3 years ago

A TV is rated at 0.1 kW. This TV is used 3 hours per day. How much energy does the TV use per month (in kWh)?

Physics

1 answer:

exis [7]3 years ago

6 0

Answer:

A.9 kWh

Explanation:

Tv is rated 0.1 kW

in one day energy used will be 0.1kW ×3hr=0.3kwh

in 30 days energy used will be 0.3kwh×30=9kwh

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It must have a medium. It must travel in empty space. Mechanical waves are waves which needs medium of propogation.

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1 year ago

If i have a kinematic equation vf^2=vi^2-2*a(xf-xi), how can i solve for xi step by step

azamat

Answer:

Explanation:

$v_f^2 = v_i^2-2a(x_f-x_i)$

Subtract both sides by $v_i^2$ :

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Divide both sides by -2*a:

$\frac{v_i^2 - v_f^2}{2a} =x_f-x_i$

Add both sides by $x_i$ :

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3 years ago

10.0 ppm 10.4 ppm 10.2 ppm 10.8 ppm 10.1 ppm 10.5 ppm 10.1 ppm Using the new instrument on the first day the technicians got a v

iren [92.7K]

Answer:

The datapoint 9.0 ppm is outlier at the 90% confidence level.

Explanation:

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standard deviation 0.2 mm

Now the mean of new values is calculated as following

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So the value as 9.0 ppm can be considered easily as outlier in this regard.

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3 years ago

Is a 10 year old supposed to be doing algebra

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If he feels like, is interested in it, and is able to grasp it, then why not ? Why not indeed ?

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2 years ago

Read 2 more answers

A piece of wire 29 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria

skelet666 [1.2K]

Answer:

Explanation:

Total length of the wire is 29 m.

Let the length of one piece is d and of another piece is 29 - d.

Let d is used to make a square.

And 29 - d is used to make an equilateral triangle.

(a)

Area of square = d²

Area of equilateral triangle = √3(29 - d)²/4

Total area,

$A = d^{2}+\frac{\sqrt3}{4}\left ( 29-d \right )^{2}$

Differentiate both sides with respect to d.

$\frac{dA}{dt}=2d- \frac{\sqrt3}{4}\times 2(29-d)$

For maxima and minima, dA/dt = 0

d = 8.76 m

Differentiate again we get the

$\frac{d^{2}A}{dt^{2}}= + ve$

(a) So, the area is maximum when the side of square is 29 m

(b) so, the area is minimum when the side of square is 8.76 m

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3 years ago