Answer:
8.7 cm
Step-by-step explanation:
The question is a 2-two-step Pythagoras theorem. (c^2 = a^2 + b^2)
Consider as such, If I were to draw a diagonal line along the base of the cube what is the length of the diagonal line. To find out that we use the theorem. We can substitute a for 5 and b for 5 as well. So
a^2 +b^2 = c^2
5^2 + 5^2 = c^2
25 + 25 = c^2
√50 = c
Then since the line side of the cube is on a 3d angle we need to do the same process again but now using the imaginary diagonal line that we just calculated and the height (5).
a^2 +b^2 = c^2
√50^2 + 5^2 = c^2
50 + 25 = c^2
√75 = c
c = 8.6602...
<em>when rounded to 1 d.p.</em>
c = 8.7
Line AB is 8.7 cm long.
Answer:
x + 5y = 30
x + 5(0) = 30
x1 = 30 y1 = 0
x + 5y = 30
1(0) + 5y = 30
y2 = 6 x2 = 0
(x1,y1) and (x2,y2)
(30,0) and (0,6)
Step-by-step explanation:
Answer:
B 7.5
Step-by-step explanation:
Answer:
Hence x = 60 and y = 50
e = 85 degrees
f = 158 degrees
Step-by-step explanation:
1) The sum of the interiror angle of the triangle is equal to the exterior
Given
Interior angles = y and 70
Exterior angle = 120 degrees
According to the law;
y + 70 = 120
y = 120-70
y = 50°
Sum of angle in the triangle is 180
x + y + 70 = 180
x + 50 + 70 = 180
x + 120 = 180
x = 180-120
x = 60
Hence x = 60 and y = 50
2) The sum of angles on a straight line is 180 degrees
40 + 55 + e = 180
95 + e = 180
e = 180 - 95
x = 85 degrees
3) Sum of angle at a point is 360 degrees
Hence 130 + 36.8 + 35.2 + f= 360
130 + 72 + f = 360
202 + f = 360
f = 360 - 202
f = 158 degrees
