Answer:
∠ ABC = 81° , ∠ FEC = 90°
Step-by-step explanation:
Since AB ≅ BC then Δ ABC is isosceles.
The median BE is therefore
The angle bisector of ∠ ABC and
BE bisects AC at right angles.
Thus
∠ ABE = ∠ CBE = 40° 30' , then
∠ ABC = 2 × 40° 30' = 81°
Since BE is perpendicular to AC then
∠ FEC = 90°
Solution
According to remainder theorem, when f(x) is divided by (x+2), Remainder =f(−2)
f(x)=5x3+2x2−6x+12
f(−2)=5(−2)3+2(−2)2−6(−2)+12
=5×−8+2×4+12+12
=−40+32=−8
∴ Remainder=−8
type of angles is complementary
equation is (3x-5)+x=90
x=23.75
7. 10 8. 20 9. 100 thats all i know
4.48
112 x 0.04 = 4.48
The letter A has at least 1 line of symmetry
