<span>The code goes like this
int temp;
temp = pos1; pos1 is assigned to temp.
pos1 = pos2; pos2 is assigned to pos1 and at this point temp is same as temp
pos2 = pos3; pos3 is assigned to pos2 and at this point temp is same as temp
pos3 = pos4; pos4 is assigned to pos3 and at this point pos4 is same as temp
pos4 = temp; pos4 is temp now and cycle rotate making pos4 getting pos1 value.</span>
2/3 x=10
Multiply 3*(2/3 x)=3*10
2x=30
x=15
A is the answer
Answer:
base = 519.62, height = 173.21 m
Step-by-step explanation:
Let the base and height of the triangle be represented by b and h respectively.
Thus,
b = 3h
Area of a triangle =
x base x height
For the given triangle,
area =
x b x 3h
=
bh
Area of the triangle =
bh
To determine the number of hectares,
36 per hectare = 486
hectare = ![\frac{486}{36}](https://tex.z-dn.net/?f=%5Cfrac%7B486%7D%7B36%7D)
= 13.5
numbers of hectares = 13.5
Area of the hectares = number of hectares x 10 000 m²
= 13.5 x 10 000
= 135000
Total area of the hectares = 135 000 m²
So that,
area of the hectares = area of the triangle
area of the triangle =
bh
135 000 =
bh
270000 = 3bh
bh = ![\frac{270000}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B270000%7D%7B3%7D)
= 90000
bh = 90000
But, b = 3h
3h x h = 90000
3
= 90000
= ![\frac{90000}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B90000%7D%7B3%7D)
= 30000
h = ![\sqrt{30000}](https://tex.z-dn.net/?f=%5Csqrt%7B30000%7D)
= 173.2051
h = 173.21 m
So that,
b = 3 x 173.2051
= 519.6153
b = 519.62
Therefore, the base of the triangle is 519.62 m, while the height is 173.21 m.
Step-by-step explanation:
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43/9 and 24/9
Working
First rewrite the mixed numbers into improper fraction.
This gives:
43/9 and 8/3
Then find the lcm of the denominators of the fraction i.e 9 and 3
Express the fractions as x/lcm
This gives 43/9 and 24/9