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lana [24]
3 years ago
15

Using the development of the atomic model.explain how scientists refine and build off each other’s findings, in order to develop

a theory.
Chemistry
1 answer:
sineoko [7]3 years ago
7 0
<span>The Atomic Model was something that was first developed by Neils Bohr. Several years later, Schrodinger took Bohr's basis of a theory and developed it into something larger. So as we can see, theories are a bit like puzzles. When first starting out, one person develops something, or has an idea on something. Others trying to either prove or disprove the original findings, will then test things in a new way, revealing more and more of the puzzle. As the puzzle becomes more and more clear, there is more and more that is revealed. Eventually, we get to a point where we have almost the entire picture, however we are still missing a few key pieces that complete the puzzle. We can see the big picture, but you can not exactly prove out what exactly the details are. This is how scientists such as Bohr and Schrodinger use each others research to build and refine theories. Eventually, we reach a point where we are only missing maybe one or two pieces, and at that point, a theory transitions into almost fact, such as evolution.</span>
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Why is a homogeneous mixture not considered a pure substance? Question 6 options: A pure substance can be separated by physical
krok68 [10]

1. Why is a homogeneous mixture not considered a pure substance?

<u><em>Answer:</em></u>

  • A pure substance can be separated by chemical means, while a mixture can be separated by physical means.

2. What is true if mass is conserved in a reaction?

<em><u>Answer:</u></em>

  • There are equal numbers of atoms on both sides.

3. <em>Methane reacts with oxygen then what are the products?</em>

<u><em>Answer:</em></u>

  • carbon dioxide and water

4. Which one of the following is not a homogeneous mixture?

<u><em>Answer:</em></u>

  • vegetable soup

5. The substance is not uniform in appearance and each part of the mixture contains a combination of different ingredients in different ratios.

<u><em>Answer:</em></u>

  • heterogeneous mixtures

6. If a solution is saturated, which of these is true?

<u><em>Answer:</em></u>

  • More solvent can be dissolved

7. Which of these substances are molecules?

<u><em>Answer:</em></u>

  • All compounds are molecules but not all molecules are compounds. Molecular oxygen (O2) and molecular nitrogen (N2) are not compounds because each is composed of a single element. So correct option is 3 and 4.

8. What makes a solution a homogeneous mixture?

<u><em>Answer:</em></u>

  • It is uniform in composition.

9. When a solute is added to a solution, why does it remain homogeneous?

<em>Answer:</em>

  • The solute dissolves.

10. The chemical formula of glucose is C6H12O6, so it is classified as a(n)

<u><em>Answer:</em></u>

  • pure substance.

11. <em>How many chlorine (Cl) atoms would be in 4 molecules of salt (4 NaCl)?</em>

<u><em>Answer:</em></u>

  • 4

12. <em>In a solution of salt and water, which component is the solute?</em>

<u><em>Answer:</em></u>

  • Salt

13. These substances are all   H2O2,   Li , NaCl , O2

<u><em>Answer:</em></u>

  • Pure Substances

14. If you have 5 grams of product after a chemical reaction, how many grams of reactants did you have at the start of the reaction?

<em>Answer:</em>

  • 5

15. What is the difference between a compound and a mixture?

<u><em>Answer:</em></u>

  • A compound is a pure substance, but a mixture is not.

16. A firework exploding would be an example of a(n) ________.

<u><em>Answer:</em></u>

  • Exothermic reaction

17. If Lavoisier heated 100 grams of powdered mercuric oxide to produce 93 grams of liquid mercury, how much oxygen would be released?

Solution

                       2HgO ==> 2Hg + O2

Mass of HgO = 100 g

Molar mass of HgO = 216.59 g/mol

Moles = mass/molar mass = 0.46 moles

From balance chemcial equation

   HgO :  O2

      2  =    1

    0.46 = (1 × 0.46 ) ÷ 2 = 0.23 moles

mass of O2 = moles× molar mass = 0.23 × 32 = 7.36 g

18. Using the Law of Conservation of Matter, determine the number of grams of iron sulfide (FeS) that will be produced in this reaction.

<em><u>Solution</u></em>

                         12g Fe + 64g S → _____ g FeS

  • According to Law of Conservation of Matter, The total mass of reactant is equal to total mass of  product , so the number of grams of iron sulfide (FeS) that will be produced in this reaction as follow.

                              12 + 64 = 76 g of FeS


Hope this Help.

 





3 0
3 years ago
Read 2 more answers
A 7.0 g sample of a hydrocarbon (a molecule that has only hydrogen and carbon) is subject to combustion analysis. The mass of CO
Akimi4 [234]

Answer: The empirical formula for the given compound is CH_2

Explanation:

The chemical equation for the combustion of compound having carbon and hydrogen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

where, 'x' and 'y' are the subscripts of carbon and hydrogen respectively.

We are given:

Mass of CO_2=22.0g

We know that:

Molar mass of carbon dioxide = 44 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 22.0 g of carbon dioxide, \frac{12}{44}\times 22.0=6g of carbon will be contained.

For calculating the mass of hydrogen:

Mass of hydrogen = Mass of sample - Mass of carbon

Mass of hydrogen = 7.0 g - 6 g

Mass of hydrogen = 1.0 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{6g}{12g/mole}=0.5moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{1.0g}{1g/mole}=1.0moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.5 moles.

For Carbon = \frac{0.5}{0.5}=1

For Hydrogen  = \frac{1.0}{0.5}=2

Step 3: Taking the mole ratio as their subscripts.

The ratio of Fe : C : H = 1 : 2

Hence, the empirical formula for the given compound is C_{1}H_{2}=CH_2

4 0
3 years ago
How many elements are in N2 and how many atoms are in N2?
Lady bird [3.3K]

Answer:

2

Explanation:

7 0
3 years ago
Read 2 more answers
PLEASE HELP ME Which of the following is a Brønsted-Lowry base but not an Arrhenius base?
never [62]
Ur answer is going to be <span>NH 3 or D AND PLEASE MARK ME AS BRAINLIEST CAUSE IVE NEVER GOT BRAINLIEST BEFORE AND HAVE A GOOD DAY !</span>
4 0
3 years ago
. the density (d) of a substance is an intensive property that is defined as the ratio of its mass (m) to its volume (v). densit
ale4655 [162]

Density is intensive because it is the ratio of two extensive properties that is mass to volume.

<h3>What is Density ?</h3>

Density is defined as mass per unit volume. S.I unit if density is kg/m³.

It is expressed as

Density = \frac{\text{Mass}}{\text{Volume}}  or d = \frac{m}{V}

<h3>What is Intensive Property ? </h3>

Intensive property is the property which does not depend on the size of the system. Intensive property can be easily identified. Intensive property is the independent property. The size does not change in this.

Example of intensive property are Density, Freezing point, melting point, colour, Lustre, etc.  

<h3>What is Extensive property ?</h3>

Extensive property is the property which depend on the substance. Extensive property cannot be easily identified.

Example of extensive property length, weight, volume, mass etc.

Thus from the above conclusion we can say that Density is intensive because it is the ratio of two extensive properties that is mass to volume.

Learn more about Density here: brainly.com/question/1354972

#SPJ4

Disclaimer: The given question is incomplete on the portal. Here is the complete question.

Question: The density (d) of a substance is an intensive property that is defined as the ratio of its mass (m) to its volume (v)

density = \frac{\text{Mass}}{\text{Volume}}  or d = \frac{m}{V}

Considering that mass and volume are both extensive properties, explain why their ratio, density is intensive.

5 0
2 years ago
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