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lana [24]
3 years ago
15

Using the development of the atomic model.explain how scientists refine and build off each other’s findings, in order to develop

a theory.
Chemistry
1 answer:
sineoko [7]3 years ago
7 0
<span>The Atomic Model was something that was first developed by Neils Bohr. Several years later, Schrodinger took Bohr's basis of a theory and developed it into something larger. So as we can see, theories are a bit like puzzles. When first starting out, one person develops something, or has an idea on something. Others trying to either prove or disprove the original findings, will then test things in a new way, revealing more and more of the puzzle. As the puzzle becomes more and more clear, there is more and more that is revealed. Eventually, we get to a point where we have almost the entire picture, however we are still missing a few key pieces that complete the puzzle. We can see the big picture, but you can not exactly prove out what exactly the details are. This is how scientists such as Bohr and Schrodinger use each others research to build and refine theories. Eventually, we reach a point where we are only missing maybe one or two pieces, and at that point, a theory transitions into almost fact, such as evolution.</span>
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Two iron balls of different mass are heated to 100°C and dropped in water. If the same amount of heat is lost by the two balls t
Kobotan [32]

Now we know that

Q = mc∆T

Where Q is y energy measured in Joules.

m is the mass measured in grams

c is the specific heat of the substance measured in joule per gram degree Celsius.

∆T is the change in temperature measured in degree Celsius.



Let Q1 be the specific heat of the lighter ball.

c1 be the specific heat of the lighter ball.

m1 be the mass of the lighter ball.

∆T1 be the change in the of the lighter ball.


Let Q2 be the specific heat of the heavier ball.

c2 be the specific heat of the heavier ball.

m2 be the mass of the heavierr ball.

∆T2 be the change in the of the heavier ball.


It has been given that the heat lost, that is Q is the same for both the balls of different mass.Which implies Q1= Q2

Specific heat(c) is the same for both the balls since both are made up of iron. c1=c2


Now heat lost by the lighter ball = heat lost by the heavier ball.

Q1= Q2

m1c1∆T1= m2c2∆T2

Since c1=c2

We get

m1/m2= ∆T2/∆T1

Thus we can say since m2>m1,∆T1> ∆T2.

Now initial temperature of both the balls are 100 degree Celsius.

∆T1 = Final temperature(T1 )-100.

∆T2= Final temperature ( T2)-100

Now since the ∆T1> ∆T2 as arrived from the above equation we can conclude that the final temperature of the ball 1 is greater than that of the ball 2. Since the ball 1 as per our assumption is the lighter ball,the final temperature of the ball which has lighter mass is greater than that of the one having a greater mass.

5 0
3 years ago
Buck's Turf Care Company mowed 233 lawns over a 11 week period. What is the average weekly rate of mowing lawns?
masya89 [10]

Answer: 21 lawns per week

Explanation:

The average weekly rate refers to how many lawns were mowed per week given that 233 were done in 11 weeks.

Rate will be given by;

= Lawns mowed / Weeks taken

= 233 / 11

= 21 lawns per week

6 0
3 years ago
What is the bond energy required to break one mole of carbon-carbon bonds​
ArbitrLikvidat [17]

Answer:

<h2><u><em>100 kcal of bond energy</em></u></h2>

<u><em></em></u>

8 0
3 years ago
Find the empirical formula of the following compounds:
Aneli [31]

The empirical formula of the following compounds 0.903 g of phosphorus combined with 6.99 g of bromine.

<h3>What is empirical formula?</h3>

The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea. As a result, both the sulfur and oxygen compounds sulfur monoxide and disulfur dioxide have the same empirical formula.

<h3>How to find the empirical formula?</h3>

Convert the given masses of phosphorus and bromine into moles by multiplying the reciprocal of their molar masses. The molar masses of phosphorus and bromine are 30.97 and 79.90 g/mol, respectively.

Moles phosphorus = 0.903 g phosphorus \frac{mol phosphorus}{ 30.97 g phosphorus}= 0.0293 mol

Moles bromine 6.99 g bromine\frac{mol bromine}{79.90 g bromine}=0.0875 mol

The preliminary formula for compound is P0.0293Bro.0875. Divide all the subscripts by the subscript with the smallest value which is 0.0293. The empirical formula is P1.00Br2.99 ≈ P₁Br3 or PBr3

To learn more about empirical formula visit:

brainly.com/question/14044066

#SPJ4

8 0
1 year ago
Whats the difference between Homogeneous and Hetrogeneuos?
irakobra [83]

Answer:

Homogeneous - With a uniform appearance

Heterogeneous - With visible differences in the mixture

Explanation:

Referring to mixtures, homogeneous looks the same throughout, while heterogeneous has particles or whatnot.  

Basically:

Homo means same

Hetero means different

6 0
3 years ago
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