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Natalija [7]
3 years ago
5

If you compare the egg to a cell, what did you learn about how water moves into or out of a cell

Chemistry
1 answer:
sleet_krkn [62]3 years ago
4 0

If we compare a cell with an egg there is a major difference between the outer membrane

in case of cell they are bounded by semi permeable membrane  

The semi permeable membrane is a selectively permeable membrane which allows the movement of only solvent molecule and not solute molecules through it.

So water can move into or out of the cell through cell membrane by a special physical process known as osmosis.  

the water will move from a low concentration gradient to high concentration gradient.

You might be interested in
Are Si valence electrons shared? <br><br> Are C valence electrons shared?
MariettaO [177]

Answer:

4

Explanation:

Si has atomic number 14 so the electronic configuration 2,8,4

5 0
3 years ago
1.86 g H2 is allowed to react with 9.75 g N2 , producing 2.87g NH3.
svet-max [94.6K]

Answer:

                     (a)  Theoretical Yield  =  10.50 g

                      (b)   %age yield  = 27.33 %

Explanation:

Answer-Part-(a)

                 The balance chemical equation for the synthesis of Ammonia is as follow;

                                          N₂ + 3 H₂ → 2 NH₃

Step 1: Calculating moles of N₂ as;

                   Moles = Mass / M/Mass

                   Moles = 9.75 g / 28.01 g/mol

                   Moles = 0.348 moles of N₂

Step 2: Calculating moles of H₂ as;

                   Moles = Mass / M/Mass

                   Moles = 1.86 g / 2.01 g/mol

                   Moles = 0.925 moles

Step 3: Finding Limiting reagent as;

According to equation,

                1 mole of N₂ reacts with  =  3 moles of H₂

So,

             0.348 moles of N₂ will react with  =  X moles of H₂

Solving for X,

                     X = 3 mol × 0.348 mol / 1 mol

                     X = 1.044 mol of H₂

It shows that to consume 0.348 moles of N₂ completely we require 1.044 mol of Hydrogen while, as given in statement we are only provided with 0.925 moles of H₂ hence, hydrogen  is limiting reagent. Therefore, H₂ will control the final yield.

Step 4: Calculating moles of Ammonia as,

According to equation,

                3 mole of H₂ produces  =  2 moles of NH₃

So,

             0.925 moles of H₂ will produce  =  X moles of NH₃

Solving for X,

                     X = 2 mol × 0.925 mol / 3 mol

                     X = 0.616 mol of NH₃

Step 5: Calculating theoretical yield of Ammonia as,

                     Theoretical Yield  =  Moles × M.Mass

                     Theoretical Yield  =  0.616 mol  × 17.03 g/mol

                     Theoretical Yield  =  10.50 g

Answer-Part-(b)

                    %age yield  = Actual Yield / Theoretical Yield × 100

                    %age yield  = 2.87 g / 10.50 g × 100

                    %age yield  = 27.33 %

4 0
3 years ago
I need an answer now please asap and you will me marked brainiest please it's missing I need it now.
valentina_108 [34]

Answer:

C. NaHCO3 → Na2CO3 + H2O + CO2

Explanation:

» For a balanced equation, the number of atoms of reactants and products must be equal.

» In equation C, the reactant side has one sodium atom while ptoduct side has 2 sodium atoms.

» The balanced equations mus be;

{ \rm{ 2NaHCO _{3(aq)} → Na _{2}CO _{3(s)}+ H _{2} O _{(l)} + }CO _{2(g)} }

7 0
2 years ago
Read 2 more answers
Y = 57.15 − 0.5 X If Y equals 5 , what is X ?<br><br> Then is Y=3, what is X?
Fiesta28 [93]

When y equals 5, x is 104.3

When y equals 3 then x is 108.3

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

y = 57.15 - 0.5x

<h3><u>If y equals 5 what is x ?</u></h3>

Substitute y = 5 in given expression

5 = 57.15 - 0.5(x)

5 = 57.15 - 0.5x

0.5x = 57.15 - 5

0.5x = 52.15

Divide both sides by 0.5

x = 104.3

Thus when y equals 5, x is 104.3

<h3><u>If y = 3 what is x ?</u></h3>

Substitute y = 3 in given expression

3 = 57.15 - 0.5(x)

3 = 57.15 - 0.5x

0.5x = 57.15 - 3

0.5x = 54.15

Divide both sides by 0.5

x = 108.3

Thus when y equals 3 then x is 108.3

7 0
3 years ago
12 Ethene gas, CH is completely burned in excess oxygen to form carbon dioxide and water
Natali [406]

Answer:

12 Ethene gas, CH is completely burned in excess oxygen to form carbon dioxide and water

The equation for this exothermic reaction is shown.

CH 30, - 200, 2H,0

The table shows the bond energies involved in the reaction

bond

bond energy

(kJ/moly

614

413

C-C

CHH

0 0

СО

495

799

O-H

467

What is the total energy change in this reaction?

A-954 kJ/mol

B-1010 kJ/mol

C-1313 kJ/mol

D-1359 kJ/mol

Explanation:

thats all you said

5 0
3 years ago
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