The group number tells you how many valence electrons are located in an atom. * True False

2. If a student drops a 2.3 g piece of magnesium into a flask of hydrochloric acid, this reaction occurs: Mg + 2HCl MgCl2 + H2

mezya [45]

1.2 L of hydrogen can be produced at a pressure of 2 atm and a temperature of 298 K.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Step 1: Write the balanced equation

Mg + 2 HCl ⇒ MgCl₂ + H₂

Step 2: Calculate the moles corresponding to 2.3 g of Mg

The molar mass of Mg is 24.31 g/mol.

2.3 g × 1 mol ÷24.31 g = 0.095 mol

Step 3: Calculate the moles of H₂ produced

0.095 mol Mg × 1 mol H₂ ÷ 1 mol Mg = 0.095 mol H₂

Step 4: Calculate the volume occupied by the hydrogen

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T÷P

V = 0.095 mol × (0.0821 atm.L/mol.K) × 298 K÷2 atm

V = 1.2 L

Learn more about the ideal gas here:

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6 0

2 years ago

Consider a mixture of two gases, A and B, confined in a closed vessel. A quantity of a third gas, C, is added to the same vessel

n200080 [17]

The question is incomplete, here is the complete question:

Consider a mixture of two gases, A and B, confined in a closed vessel. A quantity of a third gas, C, is added to the same vessel at the same temperature. How does the addition of gas C affect the following. The mole fraction of gas B?

A mixture of gases contains 10.25 g of N₂, 2.05 g of H₂, and 7.63 g of NH₃.

Answer: The mole fraction of gas B (hydrogen gas) is 0.557

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For nitrogen gas:

Given mass of nitrogen gas = 10.25 g

Molar mass of nitrogen gas = 28 g/mol

Putting values in equation 1, we get:

$\text{Moles of nitrogen gas}=\frac{10.25g}{28g/mol}=0.366mol$

For hydrogen gas:

Given mass of hydrogen gas = 2.05 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1, we get:

$\text{Moles of hydrogen gas}=\frac{2.05g}{2g/mol}=1.025mol$

For ammonia gas:

Given mass of ammonia gas = 7.63 g

Molar mass of ammonia gas = 17 g/mol

Putting values in equation 1, we get:

$\text{Moles of ammonia gas}=\frac{7.63g}{17g/mol}=0.449mol$

Mole fraction of a substance is given by:

$\chi_A=\frac{n_A}{n_A+n_B+n_C}$

Moles of gas B (hydrogen gas) = 1.025 moles

Total moles = [0.366 + 1.025 + 0.449] = 1.84 moles

Putting values in above equation, we get:

$\chi_{(H_2)}=\frac{1.025}{1.84}=0.557$

Hence, the mole fraction of gas B (hydrogen gas) is 0.557

6 0

3 years ago

What is common about the elements of a period? Select all that apply. They have the same number of electron energy levels. They

Ann [662]

Answer:

They have the same number of electron energy levels.

They transition from a metal to noble gas.

Explanation:

Periods in the periodic table of elements refer to elements in the same row. All the elements in a certain row of the periodic table;

have the same number of electron energy levels.

transition from a metal to noble gas.

4 0

2 years ago

Please help !! Science question

Lelu [443]

The answer is 2Eu + 3H2O —> Eu2O3+3H2.
Or in other words, change the first one to 3 and the second to 3 as well.

3 0

3 years ago

How many molecules of ascorbic acid(vitaminC, C6H8 O6 )are in a 500 mg tablet?

Olegator [25]

Answer:

1.71 × 10²¹ molecules

Explanation:

1 gram is equal to 1000 milligrams. The mass in grams corresponding to 500 mg is:

500 mg × (1 g / 1000 mg) = 0.500 g

The molar mass of ascorbic acid is 176.12 g/mol. The moles corresponding to 0.500 grams of ascorbic acid are:

0.500 g × (1 mol/ 176.12 g) = 0.00284 mol

In 1 mole of ascorbic acid, there are 6.02 × 10²³ molecules of ascorbic acid (Avogadro's number). The molecules in 0.00284 moles are:

0.00284 mol × (6.02 × 10²³ molecules/ 1 mol) = 1.71 × 10²¹ molecule

7 0

2 years ago

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