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3 years ago

Which statement is true about the particles of a liquid when the liquid changes into a solid?

Chemistry

1 answer:

Reptile [31]3 years ago

7 0

Answer:

they move closer to each other

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Which substance has the most thermal energy and will have the most heat flow from it?

Soloha48 [4]

Answer:

B. a nuclear reactor core (1000°C)......

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3 years ago

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The Michaelis constant for pancreatic lipase is 5 mM. At 60 C, lipase is subject to deactivation with a half-life of 8 min. Fat

Dmitriy789 [7]

Explanation:

According to the given data, we will calculate the following.

Half life of lipase $t_{1/2}$ = 8 min x 60 s/min

= 480 s

Rate constant for first order reaction is as follows.

$k_{d} = \frac{0.6932}{480}$

= $1.44 \times 10^{-3}s^{-1}
$

Initial fat concentration $S_{o}$ = 45 $mol/m^{3}$

= 45 mmol/L

Rate of hydrolysis $V_m_{o}$ = 0.07 mmol/L/s

Conversion X = 0.80

Final concentration (S) = $S_{o} (1 - X)$

= 45 (1 - 0.80)

= 9 $mol/m^{3}$

or, = 9 mmol/L

It is given that $K_{m}$ = 5mmol/L

Therefore, time taken will be calculated as follows.

t = $-\frac{1}{K_{d}}ln[1 - \frac{K_{d}}{V}{K_{M} ln (\frac{S_{o}}{S}) + (S_{o} - S)]$

Now, putting the given values into the above formula as follows.

t = $-\frac{1}{K_{d}}ln[1 - \frac{K_{d}}{V}{K_{M} ln (\frac{S_{o}}{S}) + (S_{o} - S)]$

= $-\frac{1}{1.44 \times 10^{-3}s^{-1}}ln[1 - \frac{1.44 \times 10^{-3}s^{-1}}{0.07 mmol/L/s
}{K_{M} ln (\frac{45 mmol/L
}{9 mmol/L
}) + (45 mmol/L - 9 mmol/L
)]$

= $1642.83 s \times \frac{1 min}{60 sec}$

= 27.38 min

Therefore, we can conclude that time taken by the enzyme to hydrolyse 80% of the fat present is 27.38 min.

6 0

3 years ago

There are many different ways to classify matter, but one way is to use only two categories for all matter. All matter can be cl

Strike441 [17]

I would put down C. elements or compounds

3 0

3 years ago

Which set of coefficients correctly balances the following chemical equation?__ AgNO3 + ___ MgCl2 --> ___ AgCl + ___ Mg(NO3)2

melisa1 [442]

It is C 2 1 2 1

You have to 1st balance the nitrates then balance the silvers to get the coefficients

4 0

3 years ago

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How much heat is required to raise the temperature of a 6.21 g sample of iron from 25.0 oC to 79.8 oC?

telo118 [61]

Answer:

151.1J

Explanation:

Given parameters:

Mass of iron = 6.21g

Initial temperature of iron = 25°C

Final temperature of iron = 79.8°C

Unknown:

Amount of heat = ?

Solution:

The amount of heat require to cause this temperature can be determined using the expression below;

H = m c (T₂ - T₁)

H is the amount of heat

m is the mass

c is the specific heat capacity

T is the temperature

Specific heat capacity of iron 0.444J/g°C

Insert the parameters and solve;

H = 6.21 x 0.444 x (79.8 - 25)

H = 151.1J

5 0

3 years ago