Ask question

Ask question

All categories

3 years ago

6

How to find electronegativity differences

1 answer:

lidiya [134]3 years ago

8 0

To calculate electronegativity, start by going online to find an electronegativity table. You can then assess the quality of a bond between 2 atoms by looking up their electronegativities on the table and subtracting the smaller one from the larger one. If the difference is less than 0.5, the bond is nonpolar covalent.

You might be interested in

9- Which pair of formulae represents two alkanes? (1 mark)

Ksenya-84 [330]

Answer:

A) CH4 and C8H18

Explanation:

General Formula for an Alkane = CnH2n+2

This means for every number of Carbon (C) atoms, there are twice as many Hydrogen (H) atoms with an additional two added onto that.

Therefore, if there is one Carbon Atom, and we multiply that by two, and then add an additional two, we get 4 Hydrogen atoms, so CH4, which is our first Formulae

Secondly, if we have eight Carbon Atoms, and we multiple that by two (16), and then add an additional two, we get 18 Hydrogen atoms, so C8H18, which is our second Formulae

The other Formulas do not follow this 'General Formula'

8 0

2 years ago

Convert 8.876 × 10^12 m^2 to units of km^2.

Darya [45]

Answer:

$8.876\times 10^{18}\ km^2$

Explanation:

In this problem, we need to convert $8.876 \times 10^{12}\ m^2$ to km².

We know that,

1 km = 1000 m

⇒ 1 km² = 10⁶ m²

So,

$8.876 \times 10^{12}\ m^2=8.876 \times 10^{12}\times 10^6\ km^2\\\\=8.876\times 10^{18}\ km^2$

So, $8.876 \times 10^{12}\ m^2$ is equal to $8.876\times 10^{18}\ km^2$ .

7 0

3 years ago

Convert 567 kg to grams

kodGreya [7K]

567000 would be in grams, hope this helps :)

8 0

3 years ago

Read 2 more answers

If a “sample” of pennies contained 75 heads and 25 tails, how many half‐lives would have passed since the “sample” formed. Expla

finlep [7]

..............................

8 0

3 years ago

In which pair do both compounds exhibit predominantly ionic bonding? A) KCl and CO2 B) SO2 and BaF2 C) F2 and N2O D) N2O3 and Rb

gtnhenbr [62]

Answer:

E) NaF and SrO

Explanation:

The ionic bonding occurs between atoms with a great difference in electronegativity. This usually happens between a metal and a non-metal.

<em>In which pair do both compounds exhibit predominantly ionic bonding? </em>

A) KCl and CO₂. NO. C and O are non-metals and present covalent bonding.

B) SO₂ and BaF₂. NO. S and O are non-metals and present covalent bonding.

C) F₂ and N₂O. NO. Both compounds contain non-metals and present covalent bonding.

D) N₂O₃ and Rb₂O. NO. N and O are non-metals and present covalent bonding.

E) NaF and SrO. YES. Na and Sr are metals while F and O are non-metals.

5 0

3 years ago