For this case we have by definition, that the equation of a line in the slope-intersection form is given by:
Where:
m: It's the slope
b: It is the cutoff point with the y axis
We need two points through which the line passes to find the slope:
We found the slope:
So, the equation is of the form:
We substitute a point to find "b":
Finally, the equation is:
Answer:
Option C
Hi,
The greatest common factor of 30 and 50 is 10.
Have a great day!
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
Answer:
See attachment below
Step-by-step explanation:
Answer:
the first one
Step-by-step explanation:
