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3 years ago

Ice does not need to melt into liquid water before it can return to the atmosphere as water vapor.

Physics

1 answer:

Nuetrik [128]3 years ago

6 0

That only happens when the temperature is below freezing and the air around the ice is dry.

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Find the horizontal component and the vertical component

aleksandr82 [10.1K]

Answer:

v=3.66,h-3.66

Explanation:

vertical = 10sin60 - 10sin 30

horizontal =10cos60 + 10cos 30

v = 10×0.8660-10×0.5

h = 10×0.5 + 10 × 0.8660

v=8.660-5.0 = 3.66

h= 5.0-8.660 = -3.66

8 0

2 years ago

Calculate the fraction of methyl isonitrile molecules that have an energy of 160.0 kJ or greater at 510 K .

soldi70 [24.7K]

Answer:

$4.0932672025\times 10^{-17}$

Explanation:

$E_a$ = Activation energy = 160 kJ

T = Temperature = 510 K

R = Universal gas constant = 8.314 J/mol K

The fraction of energy is given by

$f=e^{-\dfrac{E_a}{RT}}\\\Rightarrow f=e^{-\dfrac{160000}{8.314\times 510}}\\\Rightarrow f=4.0932672025\times 10^{-17}$

The fraction of energy is $4.0932672025\times 10^{-17}$

3 0

3 years ago

thuli wants to buy tv for R8500.a bank offers to loan her the money at an interest rate of 5%.she decides to pay the tv off in 3

gulaghasi [49]

Answer:

The total she has to pay is R8500 plus the 5% interest.

PLEASE ADD BRAINEEST

4 0

3 years ago

A thin film of soap with n = 1.34 hanging in the air reflects dominantly red light with λ = 642 nm. What is the minimum thicknes

wariber [46]

Answer:

The minimum thickness of the film and the wavelength of the light in air are $1.197\times10^{-7}\ m$ and 371 nm.

Explanation:

Given that,

Refractive index of soap= 1.34

Refractive index of glass= 1.55

Wavelength = 642 nm

(I). We need to calculate the minimum thickness

Using formula of thickness

$t=\dfrac{(2m+1)\lambda}{4n}$

Where, m = 0 for constrictive

Put the value into the formula

$t=\dfrac{(642\times10^{-9})}{4\times1.34}$

$t=1.197\times10^{-7}\ m$

(II). We need to calculate the wavelength

Using formula of wavelength

$\lambda=\dfrac{2nt}{m}$

Where, m = 1

Put the value into the formula

$\lambda=\dfrac{2\times1.55\times1.197\times10^{-7}}{1}$

$\lambda=371\ nm$

Hence, The minimum thickness of the film and the wavelength of the light in air are $1.197\times10^{-7}\ m$ and 371 nm.

6 0

3 years ago

Please help me↓

olga2289 [7]

Answer:

unmmm u can say that it is going mt 15s

3 0

3 years ago