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3 years ago

Ice does not need to melt into liquid water before it can return to the atmosphere as water vapor.

Physics

1 answer:

Nuetrik [128]3 years ago

6 0

That only happens when the temperature is below freezing and the air around the ice is dry.

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What is the main difference between the Schrödinger model and the Bohr atomic model?

netineya [11]

Answer:

Schrödinger believed that electrons could only exist in orbits, but Bohr stated that electrons could be found anywhere in the atom

Explanation: I got it right on test

4 0

3 years ago

How long would this acceleration last

Aleksandr-060686 [28]

It would last as long as the applied force continued, or until the accelerating object hit something.

6 0

2 years ago

what is the value of the constant for a second order reaction if the reactant concentration drops from .657 M to ,0981 M in 17 s

yaroslaw [1]

Answer : The value of the constant for a second order reaction is, $0.51M^{-1}s^{-1}$

Explanation :

The expression used for second order kinetics is:

$kt=\frac{1}{[A_t]}-\frac{1}{[A_o]}$

where,

k = rate constant = ?

t = time = 17s

$[A_t]$ = final concentration = 0.0981 M

$[A_o]$ = initial concentration = 0.657 M

Now put all the given values in the above expression, we get:

$k\times 17s=\frac{1}{0.0981M}-\frac{1}{0.657M}$

$k=0.51M^{-1}s^{-1}$

Therefore, the value of the constant for a second order reaction is, $0.51M^{-1}s^{-1}$

6 0

2 years ago

Which one doesn't belong in the group? oxygen, sulfur, selenium,

vlada-n [284]

It’s gonna be Oxygen ....

3 0

2 years ago

An electron with speed 2.45 x 10^7 m/s is traveling parallel to a uniform electric field of magnitude 1.18 x 10^4N/C . How much

cupoosta [38]

Answer:

time will elapse before it return to its staring point is 23.6 ns

Explanation:

given data

speed u = 2.45 × $10^{7}$ m/s

uniform electric field E = 1.18 × $10^{4}$ N/C

to find out

How much time will elapse before it returns to its starting point

solution

we find acceleration first by electrostatic force that is

F = Eq

here

F = ma by newton law

ma = Eq

here m is mass , a is acceleration and E is uniform electric field and q is charge of electron

put here all value

9.11 × $10^{-31}$ kg ×a = 1.18 × $10^{4}$ × 1.602 × $10^{-19}$

a = 20.75 × $10^{14}$ m/s²

so acceleration is 20.75 × $10^{14}$ m/s²

and

time required by electron before come rest is

use equation of motion

v = u + at

here v is zero and u is speed given and t is time so put all value

2.45 × $10^{7}$ = 0 + 20.75 × $10^{14}$ (t)

t = 11.80 × $10^{-9}$ s

so time will elapse before it return to its staring point is

time = 2t

time = 2 ×11.80 × $10^{-9}$

time is 23.6 × $10^{-9}$ s

time will elapse before it return to its staring point is 23.6 ns

7 0

2 years ago