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3 years ago

Ice does not need to melt into liquid water before it can return to the atmosphere as water vapor.

Physics

1 answer:

Nuetrik [128]3 years ago

6 0

That only happens when the temperature is below freezing and the air around the ice is dry.

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The brakes of an automobile are suddenly applied at the instant when its velocity is 20 m/s. If the automobile comes to a stop a

Gre4nikov [31]

Data:

Time (t) = 5 seconds
Final Velocity (v) = 0 [as the car comes to rest]
Initial velocity (u) = 20 m/s
Acceleration = ? (Negative because it is braking)

$Acceleration = \frac{v-u}{t}$
$Acceleration = \frac{0-20}{5}$
$\boxed{Acceleration = - 4m/s^2}$

3 0

3 years ago

Hii guys!! ~ i've comeback again!! could you please help me with an assignment?? i have a couple of i know questions!! thank you

Nimfa-mama [501]

Answer:

Speed = 10.24 m/s.

Explanation:

Given the following data;

Distance = 100m

Time = 9.77

To find her speed;

Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.

Mathematically, speed is given by the equation;

$Speed = \frac{distance}{time}$

Substituting into the equation, we have;

$Speed = \frac{100}{9.77}$

Speed = 10.24 meter per seconds. 

5 0

3 years ago

3.25 kcal is the same amount of energy as

PIT_PIT [208]

1 cal = 4,185 J
1 kcal = 1*10^3 cal
or
=1000 cal

8 0

3 years ago

Read 2 more answers

Which of the following (with specific heat capacity provided) would show the smallest temperature change upon gaining 200.0 J of

sergij07 [2.7K]

Answer:

A) 50.0 g Al

Explanation:

We can calculate the temperature change of each substance by using the equation:

$\Delta T=\frac{Q}{mC_s}$

where

Q = 200.0 J is the heat provided to the substance

m is the mass of the substance

$C_s$ is the specific heat of the substance

Let's apply the formula for each substance:

A) m = 50.0 g, Cs = 0.903 J/g°C

$\Delta T=\frac{200}{(50)(0.903)}=4.4^{\circ}C$

B) m = 50.0 g, Cs = 0.385 J/g°C

$\Delta T=\frac{200}{(50)(0.385)}=10.4^{\circ}C$

C) m = 25.0 g, Cs = 0.79 J/g°C

$\Delta T=\frac{200}{(25)(0.79)}=10.1^{\circ}C$

D) m = 25.0 g, Cs = 0.128 J/g°C

$\Delta T=\frac{200}{(25)(0.128)}=62.5^{\circ}C$

E) m = 25.0 g, Cs = 0.235 J/g°C

$\Delta T=\frac{200}{(25)(0.235)}=34.0^{\circ}C$

As we can see, substance A) (Aluminium) is the one that undergoes the smallest temperature change.

7 0

3 years ago

newtons third law describes the forces between two colliding objects. use this connection to explain the forces acting when you

anastassius [24]

When you kick a ball the when your foot hits the ball the force from your foot is now on the ball and if the ball bumps into somoene they might fall(if you kick hard)

6 0

3 years ago