Answer:
Spring constant = YA / L
Explanation:
Let F be the force being applied on cross sectional area A of metal bar due to which an extension of ΔL is obtained in the wire of length L then
stress = F / A
strain = ΔL /L
Young's modulus = ( F / A ) / (ΔL /L)
Y = ( F L / A ΔL )
( F / ΔL ) = ( YA / L )
Spring constant = ( F / ΔL )
Spring constant = YA / L
The formula is G=mass(1)x mass(2)
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6.67x10x-11
note that 10x-11 is in standard form but i could not write it. It is 10 raised to power negative 11
Answer:D & E are your answers just took the quiz in APEX
Explanation:
F = ma
F = force
m = mass
a = acceleration
1.5 m/s^2 = a
5 kg = m
F = ?
F = 5 * 1.5
F = 7.5 Newtons
Answer would then be :<span> Force = 7.5 N</span>
