The chemical symbol for the element zinc is Zn.
<h3>What is element?</h3>
A chemical element is the one which reacts with other elements to form a compound.
Any chemical symbol must have its first letter written in Uppercase. If the element has two letter chemical symbol, then it should be written in lowercase.
Thus, the student wrote Zn as the chemical symbol of Zinc on the whiteboard.
Learn more about element.
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Answer: Frequency factor A = 8 × 10⁹
activation energy Ea = 15.5 KJ/Mol
Explanation: to begin, let us first define the parameters given;
K₁ = 1.44 × 10⁷dm³mol⁻¹s⁻¹
K₂ = 3.03 × 10⁷ dm³mol⁻¹s⁻¹
K₃ = 6.9 × 10 dm³mol⁻¹s⁻¹
also T₁ = 300.3 K
T₂ = 341.2 K
T₃ = 392.2 K
we know that;
㏑ K₂ / K₁ = Ea/R [1/T₁ -1/T₂]
where R is given as 8.314 J/mol-k
Ea = activation energy
K₁, K₂ = rate constant
T₁, T₂ = Temperature
therefore, ㏑ (3.03 × 10⁷/ 1.44 × 10⁷) = Ea / 8.314 [1/300.3 - 1/341.2]
this gives Ea = 15496.16 J/Mol ≈ 15.5 KJ /Mol
∴ Ea = 15.5 KJ/ Mol
also given that K = A e⁻∧Ea/RT
here A = frequency factor
∴ 6.9 × 10⁷ = A e⁻ ∧(15496.16/8.314 × 392.2)
A = 7.99 × 10⁹ = 8 × 10⁹
Answer:
The position of stable equilibrium is -a
And the period of small oscillations must be: c/(ma^3)
Explanation:
Since the potential is:
We first look for a position of stable equilibrium. This posiiton must satisfy two considtions, that the first derivative of the potential must vanish at this point and the second derivative must be positive.
Which vanish for
x = a ; x =-a
The second derivative of V(x) is:
And:
Therefore:
a)
The position of stable equilibrium is -a
And the period of small oscillations must be:
(c/(ma^3))^1/2
b)
Let's find the maximum amplitude if the particle starts at this point with velocity v
If this is the case, the total energy will be:
(mv^2)/2
And the maximum amplitude will be
x = a^3/c mv^2 = (m v^2 a^3)/ c
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