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insens350 [35]
3 years ago
13

a length 650 cm of thin thread wraps around a cylinder exactly 30 times calculate the circumference and the radius of the cylind

er (take)​
Physics
1 answer:
Eduardwww [97]3 years ago
5 0

Answer:

circumference= 65/3  cm = 21.67 cm

radius R = 3.45 cm

Explanation:

To calculate the length of the circumference of the cylinder, we divide 650 cm by 30 (the number of times it wrapped exactly around it)

length of circumference= 65/3  cm = 21.67 cm

now use the formula of the circumference length to find the radius (R):

circumference length = 2 * pi * R

65/3 = 2 * pi * R

R = 65 / (6 pi)

R = 3.45 cm

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According to Oxford Dictionaries, a spit take is an act of suddenly spitting out liquid one is drinking in response to something
Tasya [4]

Answer:

The pressure is p_1 = 4051.4 \ Pa

Explanation:

From the question we are told that

     The gauge pressure at the mouth is  p_1

     The radius of the column is  r_2 =  4 \ mm  =  0.004 \ m

    The speed of the liquid outside the body is  v_2 =  3.1 \ m/s

      The area of the column is  A_2

       The area inside the mouth A_1 = 10 A_2

Generally according to continuity equation

       v_1 A_1 =  v_2 A_2

=>       v_ 1 = v_2 *  \frac{A_2}{A_1}

=>      v_ 1 = 3.1 *  \frac{1}{10}

=>        v_ 1 = 0.31 \ m/s

So

      A_1 = 10A_2

=>   \pi * r_1^2 = 10(\pi * r_2^2)

=>   r_1 = 10 * r_2

substituting values

        r_1 = 10 * 0.004

        r_1 =0.04 \ m

Now the height of inside the mouth is  h_1 =  d =  2r_1 =  2* 0.04 =  0.08\ m

Now the height of the column is  h_2 =  d =  2r_2 =  2* 0.004 =  0.008\ m

Generally according to Bernoulli's  equation

        p_1 =  [\frac{1}{2}  \rho v_2^2 + h_2 \rho g +p_2] -[\frac{1}{2} \rho * v_1^2 + h_1 \rho g ]

Now  \rho =  1000 \ kg m^{-3} which is the density of water

        p_2 is the gauge pressure of the atmosphere which is  zero

 So

       p_1 =  [(0.5 * 1000 * (3.1)^2) +(0.008 * 1000 * 9.8) + 0]-

                                                  [(0.5 * 1000 * 0.31^2) + (0.08*1000 * 9.8)]                          

       p_1 = 4051.4 \ Pa

8 0
3 years ago
What is the velocity of an 80 kg person skating across the ice with a kinetic energy of 16, 000 joules?
marysya [2.9K]

Answer:

V = 20 m/s

Explanation:

Given the following data;

Mass = 80kg

Kinetic energy = 16,000 joules

To find the velocity;

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

K.E = \frac{1}{2}MV^{2}

Where;

K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

Substituting into the formula, we have;

16000 = ½*80*V²

16000 = 40V²

V² = 16000/40

V² = 400

Taking the square root of both sides, we have;

V = 20 m/s

3 0
3 years ago
Tom kicks a soccer ball on a flat, level field giving it an initial speed of 20 m/s at an angle of 35 degrees above the horizont
SVEN [57.7K]

Answer:

(a) 2.34 s

(b) 6.71 m

(c) 38.35 m

(d) 20 m/s

Explanation:

u = 20 m/s, theta = 35 degree

(a) The formula for the time of flight is given by

T = \frac{2 u Sin\theta }{g}

T = \frac{2 \times 20 \times Sin35 }{9.8}

T = 2.34 second

(b) The formula for the maximum height is given by

H = \frac{u^{2} \times Sin^{2}\theta }{2g}

H = \frac{20^{2} \times Sin^{2}35 }{2 \times 9.8}

H  = 6.71 m

(c) The formula for the range is given by

R = \frac{u^{2} \times Sin 2\theta }{g}

R = \frac{20^{2} \times Sin 2 \times 35}{9.8}

R = 38.35 m

(d) It hits with the same speed at the initial speed.

8 0
3 years ago
How do you find the change in potential energy
ratelena [41]

P.E = mgh

This is the formula for potential energy.

This is where m is mass, g is the acceleration due to gravity, and h is height.

All you have to do is multiply all these numbers together.

3 0
3 years ago
When hot and cold air meet, the hot air rises to the top. What causes the hot air to rise???
vekshin1
Hot air rises<span> because when you </span>heat air<span> (or any other gas for that matter), it expands. When the </span>air<span> expands, it becomes less dense than the </span>air<span>around it. The less dense </span>hot air<span> then floats in the more dense cold </span>air<span> much like wood floats on water because wood is less dense than water.</span>
3 0
3 years ago
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