Question

A car traveling 23 m/s begins to decelerate at a constant rate of 5 m/s^2 . After how many seconds does the car come to a stop? (Use symbolic notation and fractions where needed.)

Answer 1

Answer:

t = 4.6 s

Explanation:

given,

initial velocity of the car = 23 m/s

declaration rate of car = 5 m/s²

final velocity of the car = ?

time taken to stop the car = ?

using equation of motion to solve the question

v = u + a t

v is final velocity

u is the initial velocity

0 = 23 - 5 t

we have used negative sign because there is deceleration

5 t = 23

$t = \dfrac{23}{5}$

t = 4.6 s

time taken to stop the car is equal to t = 4.6 s