A car traveling 23 m/s begins to decelerate at a constant rate of 5 m/s^2 . After how many seconds does the car come to a stop?
1 answer:
Answer:
t = 4.6 s
Explanation:
given,
initial velocity of the car = 23 m/s
declaration rate of car = 5 m/s²
final velocity of the car = ?
time taken to stop the car = ?
using equation of motion to solve the question
v = u + a t
v is final velocity
u is the initial velocity
0 = 23 - 5 t
we have used negative sign because there is deceleration
5 t = 23
t = 4.6 s
time taken to stop the car is equal to t = 4.6 s
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