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poizon [28]
3 years ago
11

The Earth's crust is made of tectonic plates. These plates are constantly in motion. How are earthquakes related to the movement

of tectonic plates?
A.
Two plates collide and the edges of the plate begin to crumble.
B.
Tectonic plates move against each other and release energy into the surface of the Earth.
C.
Gravity pulls down large amounts of soil on Earth's surface causing the plates to shake.
D.
Magma pushes a tectonic plate upward from under the surface of the Earth.
Physics
2 answers:
never [62]3 years ago
5 0

Answer:

I'm pretty sure it's B because I studied this topic and I'm not right I'm sorry.

atroni [7]3 years ago
5 0

Answer:

hmm its c or d

Explanation:

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A car with a momentum (impulse) of 20,000 kg m/s collides with a wall and comes to a rest in 0.1 seconds. How much
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Answer:

» Force is 200,000 Newtons

Explanation:

{ \tt{force =  \frac{impulse}{time} }} \\  \\ { \tt{force =  \frac{20000}{0.1} }} \\  \\ { \tt{force = 200000 \: newtons}}

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3 years ago
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If the kinetic and potential energy in a system are equal, then the potential energy increases. What happens as a result?
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energy of motion decrease

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yes

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3 years ago
After a nucleus undergoes radioactive decay, its new mass number is:
Ivanshal [37]
Radioactive "decay" means particles and stuff shoot OUT of a nucleus.
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Matter can undergo chemical reactions and nuclear reactions. Which
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<em>D.) state of matter</em>

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6 0
2 years ago
Charge A and charge B are 3.00 m apart, and charge A is +1.44 C and charge B is +3.10 C. Charge C is located between them at a c
Sidana [21]

Answer:

the distance from charge A to C is r₁₃= 1.216 m

Explanation:

following Coulomb's law , the force exerted by 2 point charges between themselves is:

F= k*q₁*q₂/r₁₂² , where q is charge , r is distance and 1 and 2 represents the charge A and charge B respectively , k=constant

since C ( denoted as 3) is at equilibrium

F₁₃=F₂₃

k*q₁*q₃/r₁₃²=k*q₂*q₃/r₂₃²

q₁/r₁₃²=q₂/r₂₃²

r₁₃²/q₁=r₂₃²/q₂

r₂₃=r₁₃*√(q₂/q₁)

since C is at rest and is co linear with A and B ( otherwise it would receive a net force in either vertical or horizontal direction) , we have

r₁₃+r₂₃=d=r₁₂

r₁₃+r₁₃*√(q₂/q₁)=d

r₁₃*(1+√(q₂/q₁))=d

r₁₃=d/(1+√(q₂/q₁))

replacing values

r₁₃=d/(1+√(q₂/q₁)) = 3.00 m/(1+√(3.10 C/1.44 C)) = 1.216 m

thus the distance from charge A to C is r₁₃= 1.216 m

7 0
3 years ago
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