3 years ago

Physics {deceleration}

1 answer:

7 0

Using kinematic equation, v^2 - u^2 = 2as. 5^2 - 3^2 = 2a x 16. a = 0.5m/s^2. So particle will deaccelerate at 0.5m/s^2. ( v = final velocity, u= initial velocity, a= acceleration, s= displacement.)

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shepuryov [24]

Answer:

Explanation:

For entry of light into tube of unknown refractive index

sin ( 90 - 25 ) / sinr = μ , μ is the refractive index of the tube , r is angle of refraction in the medium of tube

r = 90 - C where C is critical angle between μ and body medium in which tube will be inserted.

sin ( 90 - 25 ) / sin( 90 - C) = μ

sin65 / cos C = μ

sinC = 1.33 / μ , where 1.33 is the refractive index of body liquid.

From these equations

sin65 / cos C = 1.33 / sinC

TanC = 1.33 / sin65

TanC = 1.33 / .9063

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C= 56°

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Marina CMI [18]

I think it’s 15cm
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It moved from 0 cm to 5 cm at a constant speed of 1 cm/s.

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A machine, modeled as a simple spring-mass system, oscillates in simple harmonic motion. Its acceleration is measured to have an

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Hope this helps.

r3t40

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2 years ago