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gizmo_the_mogwai [7]
3 years ago
10

Physics {deceleration}

Physics
1 answer:
seropon [69]3 years ago
7 0
Using kinematic equation, v^2 - u^2 = 2as. 5^2 - 3^2 = 2a x 16. a = 0.5m/s^2. So particle will deaccelerate at 0.5m/s^2. ( v = final velocity, u= initial velocity, a= acceleration, s= displacement.)
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