Physics {deceleration}

Physics

1 answer:

seropon [69]3 years ago

7 0

Using kinematic equation, v^2 - u^2 = 2as. 5^2 - 3^2 = 2a x 16. a = 0.5m/s^2. So particle will deaccelerate at 0.5m/s^2. ( v = final velocity, u= initial velocity, a= acceleration, s= displacement.)

You might be interested in

I NEED HELP WITH THE LAST QUESTION ASAP D':

VMariaS [17]

Where’s the question page at??

6 0

3 years ago

A fault in which the hanging wall moves down relative to the footwall is a _____.

LuckyWell [14K]

<span>Normal fault. Normal (extensional ) fault is a displacement of a rock as a result of rock-mass movement and occurs when the crust is stretching. Because of the stretching the thickness of the crust is reduced and the crust or horizontally extended. </span>

4 0

2 years ago

Read 2 more answers

Two firefighters are trying to break through a door. One firefighter is heavy, and the other is light. If they run at the same s

frez [133]

Answer:

The Heavier Firefighter

Explanation:

Generally, more massive objects will have more intertia than less massive objects. As such it takes more force to halt a more massive object if its moving at the same speed as a smaller object. This can also be thought of in the context of Newton's second law. The more force needed to accelerate an object means the more force the object will have.

6 0

2 years ago

A man does 4,780 J of work in the process of pushing his 2.70 103 kg truck from rest to a speed of v, over a distance of 25.5 m.

wolverine [178]

Answer:

(A) Velocity will be 1.88 m/sec

(b) Force will be 187.45 N

Explanation:

We have given work done = 4780 j

Distance d = 25.5 m

(A) Mass of the truck m = $m=2.70\times 10^3kg$