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sveta [45]
2 years ago
15

An antelope moving with constant acceleration of 2m/s2 covers

Physics
1 answer:
soldier1979 [14.2K]2 years ago
6 0

Explanation:

we use the formula for that 6s duration ....

<h2> S = ut + 1/2 at² </h2><h3>s = displacement </h3><h3>u = initial velocity </h3><h3>a = acceleration </h3><h3>t = time </h3>

so , S = (5 × 6) + (1/2 × 2 × 6 × 6 )

S = 30 + 36

<h3> S = 66m</h3>

and we can use this formula to find the final velocity.......

<h2> V = U + at </h2><h3>V = final velocity </h3><h3>a = acceleration </h3><h3>u = initial velocity </h3><h3>t = time </h3>

so , V = 5 + (2×6)

V = 5 + 12

<h3> V = 17m/s </h3>
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What is the largest meteoroid that has collided with this planet
Burka [1]

Chicxulub. It's the most famous cataclysm ever, the meteorite that probably snuffed out the dinosaurs (along with three-quarters of all life on Earth) when it smashed into our planet 65 million years ago. The crater it left behind is actually one of the youngest and most accessible in the solar system.


6 0
3 years ago
A constant net torque is applied to an object. Which one of the following will NOT be constant?
love history [14]

Answer:

B) Angular velocity

Explanation:

The equivalent of Newton's second law for the rotational motions can be written as:

\tau = I \alpha

where

\tau is the net torque applied to the object

I is the moment of inertia

\alpha is the angular acceleration

From the formula we see that when a constant net torque \tau is applied, then the object also has a constant angular acceleration, \alpha.

But we also know that

\alpha = \frac{d\omega}{dt}

where \omega is the angular velocity: so, a constant angular acceleration means that the angular velocity of the object is changing, so the correct answer is

B) Angular velocity

(moment of inertia and center of gravity do not change since they only depend on the mass and the geometry/shape of the object, which do not change)

7 0
3 years ago
The diameter of a hydrogen atom is 0.000000000106 m. How can this
Andreas93 [3]

Answer:

The diameter of a hydrogen atom based on scientific notation is 1.06 x 10^-10 m

8 0
3 years ago
The age of the universe is around 100,000,000,000,000,000s. A top quark has a lifetime of roughly 0.000000000000000000000001s. W
Maslowich

Answer:

10⁴¹ s quark top lives have been in the history of the universe.

Explanation:

You need to determine how many quark top lives there have been in the history of the universe, that is, what is the age of the universe divided by the lifetime of a top quark. Expressed in a formula, this is:

t\frac{Age of the universe}{Lifetime of a top quark}

Yo know that the "Age of the universe" is 100,000,000,000,000,000  which can also be expressed as 10¹⁷ s .

You also know that the "Lifetime of a top quark" is 0.000000000000000000000001 which can also be expressed as 10⁻²⁴ s.

Then t=\frac{10^{17} }{10^{-24} }

Recalling that the result of dividing two powers of the same base is another power with the same base where the exponent is the subtraction of the initial exponents, it is possible to calculate this division as follows:

t=10^{17-(-24)}

t=10^{17+24}

<u><em>t=10⁴¹ s</em></u>

So <u><em>10⁴¹ s quark top lives have been in the history of the universe.</em></u>

5 0
3 years ago
A particle travels in a circle of radius 76 cm and completes one revolution in 4.5 s. What is the centripetal acceleration of th
Dimas [21]

r = radius of the circle traveled by the particle = 76 cm = 0.76 m

T = time period of revolution for the particle = 4.5 s

w = angular velocity of the particle

angular velocity of the particle is given as

w = 2π/T

inserting the values

w = 2 (3.14)/4.5

w = 1.4 rad/s

a = centripetal acceleration of the particle in the circle

centripetal acceleration is given as

a = r w²

inserting the values

a = (0.76) (1.4)²

a = 1.5 m/s²

3 0
3 years ago
Read 2 more answers
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