Answer:
the law of motion
Explanation:
because the wheels are moving it means motion i am not sure which number law it is but I believe that it is 2nd but u should look it up to be safe
Answer:
19.48 m
Explanation:
Gravitational potential energy = mgh
Current weight = 539 N
Weight = mg = 539 N
Mass x Acceleration = 539 N
Mass x 9.81 = 539
Mass = 54.94 kg
Gravitational potential energy = mgh = 10500 J
54.94 x 9.81 x h = 10500
h = 19.48 m
Height of sitting = 19.48 m
Answer: V = 15 m/s
Explanation:
As stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. The observed frequency the car will be experiencing will be addition of the two frequency. That is,
F = 2.1 × 10^10 + 1030 = 2.100000103×10^10Hz
Using doppler effect formula
F = C/ ( C - V) × f
Where
F = observed frequency
f = source frequency
C = speed of light = 3×10^8
V = speed of the car
Substitute all the parameters into the formula
2.100000103×10^10 = 3×10^8/(3×10^8 -V) × 2.1×10^10
2.100000103×10^10/2.1×10^10 = 3×108/(3×10^8 - V)
1.000000049 = 3×10^8/(3×10^8 - V)
Cross multiply
300000014.7 - 1.000000049V = 3×10^8
Collect the like terms
1.000000049V = 14.71429
Make V the subject of formula
V = 14.71429/1.000000049
V = 14.7 m/s
The speed of the car is 15 m/s approximately
Answer:
lead with Z = 82 is transformed into Bismuth with Z = 73
The Po with Z = 84 becomes Pb with Z = 82
Explanation:
Beta decay occurs when a neutron emits an electron and an anti neutrino from the atomic nucleus, therefore the atomic number of the material increases by one unit.
Pb + e + ν → Bi
lead with Z = 82 is transformed into Bismuth with Z = 73
In alpha decay, a helium nucleus is emitted from the nucleus of the atom, therefore the atomic number decreases by two units.
Po +α → Pb
The Po with Z = 84 becomes Pb with Z = 82
Answer:
The angle of separation is
Explanation:
From the question we are told that
The angle of incidence is 
The refractive index of violet light in diamond is 
The refractive index of red light in diamond is 
The wavelength of violet light is
The wavelength of red light is
Snell's Law can be represented mathematically as

Where
is the angle of refraction
=> 
Now considering violet light

substituting values




Now considering red light

substituting values




The angle of separation between the red light and the violet light is mathematically evaluated as

substituting values

