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horrorfan [7]
3 years ago
13

What is the length of an aluminum rod at 65°C if its length at 15°C is 1.2 meters?

Physics
2 answers:
lana66690 [7]3 years ago
3 0

<em><u>Answer:</u></em>

The new length is 1.20138 m

<em><u>Explanation:</u></em>

<u>1- We get the increase in length:</u>

The old length = 1.2 m

The coefficient of expansion of of aluminum is 23 * 10⁻⁶ /K.

The old temperature is 15°C.

The new temperature is 65°C

The increase in length= old length * coefficient of expansion *change in temperature

The increase in length = 1.2 * 23 * 10⁻⁶ * (65-15)

The increase in length = 0.00138 m

<u>2- getting the new length:</u>

new length = old length + increase in length

new length = 1.2 + 0.00138

new length = 1.20138 m

Hope this helps :)

Radda [10]3 years ago
3 0
<span>1.201386 meters at 65 degrees C.      
 Will be your answer!

Hope I Helped!</span>
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Answer:

Acceleration = -0.75 m/s²

Explanation:

Given the following data;

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Final velocity = 15 m/s

Time = 12 seconds

To find the acceleration of the automobile;

Acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac {final \; velocity  -  initial \; velocity}{time}

Substituting into the formula, we have;

Acceleration = \frac{15 - 24}{12}

Acceleration = \frac{-9}{12}

Acceleration = -0.75 m/s²

Therefore, the automobile is decelerating because its final velocity is lesser than its initial velocity, leading to a negative value.

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3 years ago
When you enter a toll road, your ticket is stamped 1:00 p.m. When you leave, after traveling 55 miles, your ticket is stamped 2:
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Which best describes the forces identified by Newton’s third law of motion?
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How are the components of a heterogeneous mixture distributed?
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What is the distance from axis about which a uniform, balsa-wood sphere will have the same moment of inertia as does a thin-wall
andrey2020 [161]

Answer:

D_{s} ≈ 2.1 R

Explanation:

The moment of inertia of the bodies can be calculated by the equation

     I = ∫ r² dm

For bodies with symmetry this tabulated, the moment of inertia of the center of mass

Sphere               Is_{cm} = 2/5 M R²

Spherical shell   Ic_{cm} = 2/3 M R²

The parallel axes theorem allows us to calculate the moment of inertia with respect to different axes, without knowing the moment of inertia of the center of mass

    I = I_{cm} + M D²

Where M is the mass of the body and D is the distance from the center of mass to the axis of rotation

Let's start with the spherical shell, axis is along a diameter

     D = 2R

    Ic = Ic_{cm} + M D²

    Ic = 2/3 MR² + M (2R)²

    Ic = M R² (2/3 + 4)

    Ic = 14/3 M R²

The sphere

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    Is = Ic

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    D_{s}² = R² (14/3 - 2/5)

    D_{s} = √ (R² (64/15)

    D_{s} = 2,066 R

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3 years ago
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