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2 years ago

What is the length of an aluminum rod at 65°C if its length at 15°C is 1.2 meters?

Physics

2 answers:

lana66690 [7]2 years ago

3 0

Answer:

The new length is 1.20138 m

Explanation:

1- We get the increase in length:

The old length = 1.2 m

The coefficient of expansion of of aluminum is 23 * 10⁻⁶ /K.

The old temperature is 15°C.

The new temperature is 65°C

The increase in length= old length * coefficient of expansion *change in temperature

The increase in length = 1.2 * 23 * 10⁻⁶ * (65-15)

The increase in length = 0.00138 m

2- getting the new length:

new length = old length + increase in length

new length = 1.2 + 0.00138

new length = 1.20138 m

Hope this helps :)

Radda [10]2 years ago

3 0

1.201386 meters at 65 degrees C.
Will be your answer!

Hope I Helped!

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2 years ago

Suppose you wanted to hold up an electron against the force of gravity by the attraction of a fixed proton some distance above i

SCORPION-xisa [38]

Answer:

The value is $r = 5.077 \ m$

Explanation:

From the question we are told that

The Coulomb constant is $k = 9.0 *10^{9} \ N\cdot m^2 /C^2$

The charge on the electron/proton is $e = 1.6*10^{-19} \ C$

The mass of proton $m_{proton} = 1.67*10^{-27} \ kg$

The mass of electron is $m_{electron } = 9.11 *10^{-31} \ kg$

Generally for the electron to be held up by the force gravity

Then

Electric force on the electron = The gravitational Force

i.e

$m_{electron} * g = \frac{ k * e^2 }{r^2 }$

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7 0

3 years ago

what is the momentum of a child and a wagon if the total mass of the child and wagon is 22kg and the velocity is 1.5m/s?

antoniya [11.8K]

Answer:

33 kg m/s

Explanation:

The momentum of an object is given by:

$p=mv$

where

m is the mass of the object

v is the velocity of the object

In this problem, the total mass of the child and the wagon is m =22 kg, while the velocity is v = 1.5 m/s, therefore the momentum is

$p=mv=(22 kg)(1.5 m/s)=33 kg m/s$

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3 years ago

Starting fom rest, a car accelerates at a constant rate, reaching 88 km/h in 12 s. (a) What is its acceleration? (b) How far doe

JulsSmile [24]

Answer:

(A) $a=2.0.37m/sec^2$

(B) s = 146.664 m

Explanation:

We have given car starts from the rest so initial velocity u = 0 m /sec

Final velocity v = 88 km/hr

We know that 1 km = 1000 m

And 1 hour = 3600 sec

So $88km/hr=88\times \frac{1000}{3600}=24.444m/sec$

Time is given t = 12 sec

(A) From first equation of motion v = u+at

So $24.444=0+a\times 12$

$a=2.0.37m/sec^2$

So acceleration of the car will be $a=2.0.37m/sec^2$

(b) From third equation of motion $v^2=u^2+2as$

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Answer:

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