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snow_tiger [21]
3 years ago
5

An object is placed at zero zero on a Number line. It moves three units to the right, then four units to the left, and then 60 u

nits to the right. What is the displacement of the object
Physics
1 answer:
STatiana [176]3 years ago
7 0

Answer:

the displacement of the object is 5 units

Explanation:

The computation of the displacement of the object is shown below:

= Move to the right + move to the right - move to the left

= 6 units + 3 units - 4 units

= 9 units - 4 units

= 5 units

Hence, the displacement of the object is 5 units

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What is direct current? In which direction does current go according to the electron flow convention?
KatRina [158]

Answer:

Answer to the question is:

Explanation:

Direct Current:

It is that current where electrons circulate in the same amount and sense in time, that is, flowing in the same direction. Its polarity is invariable and causes a current of relatively constant amplitude to flow through a load. This type of current is known as direct current (DC), and is generated by a battery.

the current of electrons will leave the negative terminal of the battery, (because they repel each other and also repel free electrons in the copper conductor), and go to the positive terminal where there is a lack of electrons, passing through the circuit to which it is connected. In this way the electric current is produced.

4 0
3 years ago
An ultrasound unit is being used to measure a patient's heartbeat by combining the emitted 2.0 MHz signal with the sound waves r
alexandr402 [8]
Hi there, 
for this question we have:
Signal 2.0 MHz = Emitted so we can call it f_e
and we need the Reflected = f_{r}
In this question, we have a source which goes to the heart and a reflected which comes back from the heart and we need the speed of the reflected.
So you should know that the speed of reflected is lower than the source(Emitted). 
we also know: ΔBeat frequency(max) = 560 Hz = f_{b}
so we have: 
f_{e} - f_{r} = f_{b}
so frequency of Reflected is: 
2.0 × 10^6 Hz - 560 Hz = 1.99 × 10^6 Hz = f_{r}
now you know that Lambda = v/f 
so if we find the lambda with our Emitted then we can find v with the Reflected: 
Lambda = 1540(m/s) / 2.0 × 10^6 Hz = 7.7 × 10^-4 m 
=> v_{max} = (lambda)(f_{r} 
=> 7.7 × 10^-4m (1.99 × 10^6Hz) = 1532 m/s 
so the v_{max} is equal to 1532 m/s :)))
This question is solved by two top teachers as fast as they could :))
I hope this is helpful
have a nice day

8 0
4 years ago
What term best describes the regular path of a spacecraft or other object around a planetary body?
Law Incorporation [45]
B. Orbit. The planets orbit the sun, the moon orbits earth, etc.
7 0
3 years ago
A double slit that is illuminated with coherent light of wavelength 644 nm produces a pattern of bright and dark fringes on a sc
shutvik [7]

Answer:

2.77 cm

Explanation:

d = separation between the slits = 2783 x 10⁻⁹ m

\lambda = wavelength of coherent light = 644 nm = 644 x 10⁻⁹ m

D = Distance of the screen = 6 cm = 0.06 m

y_{n} = Position of nth bright fringe

Position of nth bright fringe is given as

y_{n} = \frac{nD\lambda }{d}  

for n = 2

y_{2} = \frac{nD\lambda }{d}  

y_{2} = \frac{(2)(0.06)(644\times10^{-9}))}{2783\times10^{-9}}

y_{2} = 0.0278 m

for n = 4

y_{4} = \frac{nD\lambda }{d}  

y_{4} = \frac{(4)(0.06)(644\times10^{-9}))}{2783\times10^{-9}}

y_{4} = 0.0555 m

Distance between 4th and 2nd bright fringes is given as

w = y_{4} - y_{2} = 0.0555 - 0.0278 = 0.0277 m

w = 2.77 cm

8 0
3 years ago
PLEASE HELP! The tendency of an object to resist any change in its motion is called
soldi70 [24.7K]

inertia is the answer!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

4 0
3 years ago
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