We're adding two vectors here. The first is 300 Newtons to the right, which we can write as (300, 0), meaning 300 to the right, 0 up.
The second is 300 at let's say a 45 degree angle down. For the components we have an isosceles right triangle with hypotenuse 300, so the components are both magnitude 300/√2 = 150√2. So we can write this vector (150√2, -150√2), the negative sign because it points down in the y direction.
Adding is componentwise. The resulting force is (300+150√2, -150√2).
That has square magnitude
r² = (300+150√2)² + (-150√2)² = 150² ( (2+√2)² + (√2)² )
= 150²( (6 + 4√2) + 2)
= 300²(2+√2)
so
r = 300 √(2+√2) Newtons
That's the answer; I'm not sure if your class expects a calculator approximation, which is 554.3 Newtons.
Answer: the answer would be C trust me i took the test if its not that its b
hope that helps
Explanation: i took the test
Answer:
If a car is moving at a <em><u>constant velocity of 10 m/s,</u></em> there will be no change in the velocity per time.
Acceleration is the rate of change of velocity
Acceleration=(Final velocity-Initial velocity)/Time
Acceleration=(10m/s-10m/s)/Time= <em><u>0 m/s²</u></em>
<h3>★ <u>0 m/s²</u> is the right answer. </h3>
heat = mass x spec heat x temp rise
40.5=15.4x10^-3xspec heatx11.2
Lighting is the static electricity stored in the clouds that is disposed to the earth.
