Answer:
in oil film λ = 303.57 10⁻⁹ m
in the water film λ = 319.55 10⁻⁹ m
Explanation:
When electromagnetic radiation reaches a material, its propagation is by a process that we call absorption and reflection,
when light reaches a surface it has a mass much greater than the mass of the photons (m = 0), therefore there is an elastic collision where the frequency does not change, due to the speed of light in the material medium changes, therefore the only possibility is that the wavelength in the material changes, to maintain the relationship
v = λ f
in the void we have
c = λ₀ f
we divide the two expression
c / v = λ₀ / λ
the refractive index is
n = c / v
n = λ₀ /λ
λ = λ₀ / n
let's calculate
in oil film
λ = 425 10⁻⁹ / 1.40
λ = 303.57 10⁻⁹ m
in the water film
λ = 425 10⁻⁹ / 1.33
λ = 319.55 10⁻⁹
those wavelengths are in the ultraviolet
Rock fragments that are cemented together and compacted over time turn into sedimentary rock.
the whole process can be summed up as the combination of weathering of rocks to form sediments, transport of the sediments to form deposits, cementation of deposits to forms the sedimentary rocks.
Answer:
C. 8I.
Explanation:
As moment of inertia for a bar is proportional to the product of its mass and the square of its length, doubling the mass will double the moment of inertia. Doubling the length will quadruple the moment of inertia. Doing both will make the moment of inertia 2(4) = 8 times larger
Answer:
Our estimate not done correctly because the width was unrealistic.
Explanation:
Given that,
Length = 6 m
Width = 0.5 m
We need to calculate the area of rectangular floor
Using formula of area
Where, l = length
w= width
Put the value into the formula
We need to find why this estimate not done correct
Using given data
We can say that,
We assume width was unrealistic.
The length of room is 6 m.
We know that,
So, the length would be 20 feet.
The width of room is 0.5 m.
The width of room would be 1.64 feet.
So, the area will be
Hence, Our estimate not done correctly because the width was unrealistic.
Resolving vectors question. See diagram enclosed.