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Alisiya [41]
2 years ago
14

Please answer ................

Chemistry
1 answer:
nataly862011 [7]2 years ago
3 0

Answer:

Explanation:

i. SO2

ii. Na2O

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What is determined by calculating the slope of the position versus time graph distance
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Answer:

Determining the Slope on a p-t Graph. It was learned earlier in Lesson 3 that the slope of the line on a position versus time graph is equal to the velocity of the object. ... If the object has a velocity of 0 m/s, then the slope of the line will be 0 m/s. The slope of the line on a position versus time graph tells it all.

Explanation:

#<em>c</em><em>a</em><em>r</em><em>r</em><em>y</em><em>o</em><em>n</em><em>l</em><em>e</em><em>a</em><em>r</em><em>n</em><em>i</em><em>n</em><em>g</em><em> </em>

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3 years ago
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Help I think the answer is either A or D.
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Answer:

D

Explanation:

Miss Girl. Snow isn't in Nevada-

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Darwin called this idea of certain traits being selected in order for an organism to reproduce sexual selection. In crickets and
tamaranim1 [39]

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If the energy difference between two electronic states is 214.68 kJ / mol , calculate the frequency of light emitted when an ele
atroni [7]

{\qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

Energy difference btween the two electronic states can be expressed as :

{ \qquad \sf  \dashrightarrow \: \Delta E = h\nu}

[ h = planks constant,{\: \nu }= frequency ]

\qquad \sf  \dashrightarrow \:214.68 = 39.79 \times 10 {}^{ - 14}  \times  \nu

\qquad \sf  \dashrightarrow \: \nu =  \cfrac{214.68}{39.79 \times 10 {}^{ - 4} }

\qquad \sf  \dashrightarrow \: \nu =  \cfrac{214.68}{39.79 }  \times 10 {}^{14}

\qquad \sf  \dashrightarrow \: \nu  \approx  5.395 \times10 {}^{14}  \:\:hertz

5 0
2 years ago
A certain first-order reaction is 27.5 percent complete in 8.90 min at 25°C. What is its rate constant?
jeyben [28]

Answer:

k= 0.145min^{-1}

Explanation:

Hello there!

In this case, according to the given information, it turns out necessary for us remember that the first-order kinetics is given by:

ln(A/A_0)=-kt

Whereas the 27.5% complete means A/Ao=0.275, and thus, we solve for the rate constant as follows:

k=\frac{ln(A/A_0)}{-t}

Then, we plug in the variables to obtain:

k=\frac{ln(0.275)}{-8.90min}\\\\k= 0.145min^{-1}

Regards!

4 0
3 years ago
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