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svet-max [94.6K]
4 years ago
10

Consider the reaction below.

Chemistry
1 answer:
Law Incorporation [45]4 years ago
6 0

Answer:

  • <u>First choice: 0.042</u>

Explanation:

Given decomposition reaction:

  • 1PCl₅ (g) ⇄ 1PCl₃ + 1Cl₂(g)

Equilibrium constant:

  • K_{eq}=\frac{[PCl_3]^1[Cl_2]^1}{[PCl_5]^1}

Stoichiometric coefficients and powers equal to 1 are not usually shown as they are understood, but I included them in order to shwow you how they intervene in the equilibrium expressions: each concentration is raised to a power equal to the respective stoichiometric coefficient in the equilibrium equation.

So, your calculations are:

K_{eq}=\frac{(0.020M)(0.020M)}{0.0095M}=0.042M

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A sample of gasoline has a mass of 595.0 lb and a volume of 14.0 ft^3. What is its specific gravity?
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Explanation:

The given data is as follows.

            mass of gasoline = 595.0 lb

            volume of gasoline = 14.0 ft^{3}

As it is known that density is the amount of mass of a substance divided by its volume.

So, density of gasoline will be as follows.

                Density = \frac{mass}{volume}

                              = \frac{595.0 lb}{14.0 ft^{3}}

                              = 42.5 lb/ft^{3}

As, 1 lb = 0.4536 kg and 1 ft = 0.3048 m. Now, putting these values into the above equation (1) as follows.

                       Density = 42.5 lb/ft^{3}

                                     = 42.5 \times \frac{0.4536 kg}{(0.3048 m)^{3}}

                                     = 680.792 kg/m^{3}    

                                     = 680.8 kg/m^{3} (approx)

Density of water is 1000 kg/m^{3}. To measure specific gravity of gasoline, the formula will be as follows.

               specific gravity of gasoline = \frac{\text{density of gasoline}}{\text{density of water}}    

                                         = \frac{680.8 kg/m^{3}}{1000 kg/m^{3}}

                                         = 0.681

Thus, we can conclude that the specific gravity of gasoline is 0.681.

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