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4 years ago

Consider the reaction below.

Chemistry

1 answer:

Law Incorporation [45]4 years ago

6 0

Answer:

First choice: 0.042

Explanation:

Given decomposition reaction:

1PCl₅ (g) ⇄ 1PCl₃ + 1Cl₂(g)

Equilibrium constant:

$K_{eq}=\frac{[PCl_3]^1[Cl_2]^1}{[PCl_5]^1}$

Stoichiometric coefficients and powers equal to 1 are not usually shown as they are understood, but I included them in order to shwow you how they intervene in the equilibrium expressions: each concentration is raised to a power equal to the respective stoichiometric coefficient in the equilibrium equation.

So, your calculations are:

$K_{eq}=\frac{(0.020M)(0.020M)}{0.0095M}=0.042M$

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pashok25 [27]

Answer: 1.14mol

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31.9g(1/28)=1.14mol N2

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4 years ago

the ph of a solution of HCl in water is found to be 2.50. what volume of water would you add to 1.00L of this solution to raise

morpeh [17]

Answer:

To raise the pH of the solution to 3.10 we have to add 2.34 L of water.

Explanation:

Given that the pH of the solution of HCl in water is 2.5. Here the solution’s pH is changing from 2.5 to 3.10 which means the acidic nature of the solution is decreasing here on dilution. $[H^+]$ ions contribute to a solution’s acidic nature and $[OH^-]$ contribute to a solution’s basic nature.

The equation connecting the concentration of $[H^+]$ and pH of a solution is pH= $-log[H^+]$

 $[H^+]= 10^(^-^p^H^)$ $[H^+]= 10^(^-^2^.^5^)=0.00316$ 

When the pH is $3.1 [H^+ ]= 10^(^-^3^.^1^)=0.000794$ 

On dilution the concentration of a solution decreases and volume increases.

 $M_1 V_1 = M_2 V_2$ 

 $0.00316 \times 1 = 0.000794 \times V_2$ 

 $V_2 = \frac{(0.00316 \times 1)}{0.000794} =3.24$ 

Volume of water to be added $=3.24-1$ 

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3 years ago

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pshichka [43]

Which of the following is a surface event that takes place during the rock cycle? Erosion

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Pie

Answer:

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Explanation:

They will determine many of the atoms traits since they are involved in bonding with other atoms.

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