Answer:
hope this helped :( got this from my friend a long time ago but still not sure if it's really correct this
What Mass of glucose is needed to prepare 235mL of 22% w/v glucose?
2 answers:
You might be interested in
P₄0₆ + 20₂
⇒ P₄0₁₀
Explanation:
The overall equation for the reaction that produces P₄0₁₀ is :
P₄0₆ + 20₂
⇒ P₄0₁₀
Now let us derive this equation:
Given equations:
P₄ + 30₂
⇒ P₄0₆
equation 1;
P₄ + 50₂
⇒ P₄0₁₀
equation 2;
To get the overall combined equation, the equation 1 must be reversed and added to equation 2:
P₄0₆ ⇒ P₄
+ 30₂
equation 3
+
equation 2:
P₄ + 50₂
+ P₄0₆
⇒ P₄0₁₀
+ P₄
+ 30₂
cancelling specie that appears on both sides and removing excess oxygen gas on the reactant side gives;
P₄0₆ + 20₂
⇒ P₄0₁₀
learn more:
Net equation brainly.com/question/2947744
#learnwithBrainly