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Dovator [93]
3 years ago
11

What Mass of glucose is needed to prepare 235mL of 22% w/v glucose?

Chemistry
2 answers:
rosijanka [135]3 years ago
8 0

Answer: 8 grams of glucose are needed to prepare 400. ml of a 2.0%(m/v) glucose solution. 8 grams of glucose are needed to prepare 400.Oct 6, 2017

uysha [10]3 years ago
4 0

Answer:

8 grams of glucose are needed to prepare 400. ml of a 2.0%(m/v) glucose solution. 8 grams of glucose are needed to prepare 400

Explanation:

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23 grams of Acetaminophen is equal to how many moles?
larisa86 [58]

Answer:

0.15215407

Explanation:

Im not 100% sure if this is correct!

5 0
3 years ago
Which is not a compound?<br><br> oxygen gas<br> water<br> silicon dioxide <br> carbon dioxide gas
olchik [2.2K]

Answer:

Oxygen gas

Explanation:

It is a pure element. The rest are compounds made up of two or more elements. For eg silicon dioxide is made of silicon and oxygen.

7 0
4 years ago
The side chain (r group) of the amino acid serine is ch2oh. The side chain of the amino acid leucine is ch2ch(ch3)2. Where would
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The answer is leucine would be in the interior, and serine would be on the exterior of the globular protein.

The side chain (R group) of the amino acid serine is CH₂OH. The side chain of the amino acid leucine is CH₂CH(CH₃)₂. In globular protein, leucine found in the interior, and serine found on the exterior. The nature of side chain decides the amino acid position in the globular protein , as CH₂CH(CH₃)₂ this is hydrophobic and CH₂OH is hydrophlic.

8 0
4 years ago
ASAP WHAT ARE THE ANSWERS FOR 3,4,5,6
storchak [24]
3 should be B hop this helps
3 0
3 years ago
Read 2 more answers
50.00 mL of unknown calcium hydroxide solution is titrated with 0.250 M standard nitric acid solution. If 43.43 mL of the standa
notsponge [240]

Answer: Molarity of the unknown calcium hydroxide solution is 0.217 M.

Explanation:

Given: V_{1} = 50.00 mL,     M_{1} = ?

V_{2} = 43.43 mL,         M_{2} = 0.250 M

Formula used is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula as follows.

M_{1}V_{1} = M_{2}V_{2}\\M_{1} \times 50.00 mL = 0.250 M \times 43.43 mL\\M_{1} = \frac{0.250 M \times 43.43 mL}{50.00 mL}\\= 0.217 M

Thus, we can conclude that molarity of the unknown calcium hydroxide solution is 0.217 M.

5 0
3 years ago
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