Answer:
d- it is an acid because it increases the concentration of hydronium ions
Explanation:
HCl; hydrochloric acid is an acid because it increases the concentration of hydronium ions when in solutions.
An acid is a substance that interacts with water to produce excess hydroxonium ions H₃O⁺ in an aqueous solution.
For example:
HCl + H₂O → H₃O⁺ + Cl⁻
HCl is classified as a strong acid due to its complete ionization when in solutions.
C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O
is a combustion reaction
Explanation:
In a combustion reaction a chemical substance (usually organic substances) are reacted with oxygen to form the most stable oxides and heat.
CH₄ + 2 O₂ → CO₂ + 2 H₂O
In a double displacement reaction two compounds exchange elements.
AB + CD → AC + BD
In a decomposition reaction a compound is split into simpler substances.
AB → A + B
In a synthesis reaction two elements are combined to form another compound. A + B → AB
In a single displacement reaction a compound exchange one of its elements.
AB + C → AC + B
Learn more about:
types of chemical reactions
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Answer:
The correct answer is a scientific law.
Explanation:
The laws of science or scientific laws refer to the statements, which predict or illustrate an array of natural processes. It is a statement based on observations or spontaneous experiments, which illustrate some characteristics of the natural world.
The term law exhibits different uses in various circumstances, that is, across all the branches of natural science. The laws are formulated through data and can be further created via mathematics, in all the conditions, they are indirectly or directly based on empirical evidence. The scientific laws recapitulate the outcomes of observations or experiments, generally within some point of application.
Answer:
% composition O = 19.9%
% composition Cu = 80.1%
Explanation:
Given data:
Total mass of compound = 3.12 g
Mass of copper = 2.50 g
Mass of oxygen = 3.12 - 2.50 = 0.62 g
% composition = ?
Solution:
Formula:
<em>% composition = ( mass of element/ total mass)×100</em>
% composition Cu = (2.50 g / 3.12 g)×100
% composition Cu = 0.80 ×100
% composition Cu = 80.1%
For oxygen:
<em>% composition = ( mass of element/ total mass)×100</em>
% composition O = (0.62 g / 3.12 g)×100
% composition O = 0.199 ×100
% composition O = 19.9%
