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3 years ago

A student is heating a chemical in a beaker with a Bunsen burner.

2 answers:

7 0

The student should wear a lab coat that will protect the body from potential spilling of the substance, protective eyewear in case the compound will explode and latex gloves to have some protection against the chemicals which may burn the skin. Besides the respiratory mask, the heating should be carried out in a laboratory hood to prevent the inhalation of the toxic compound which may be released if the chemical will burn. After the heating is complete the beaker should be handled with wooden pliers because is very hot and so avoiding thermal burning.

Explanation:

gogolik [260]3 years ago

3 0

Explanation:

A lab coat protects the student from any spillage of the chemicals on his body. Gloves should protect the student from getting the chemical on his hands as he works. Safety goggles also protect the eyes from any splatter than may be directed towards the eyes.

If the heating produces fumes he must heat the chemical near a window and with the mouth of the beaker facing away from him/her. A safety cabinet should be used if the fumes are considered harmful to inhale.

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If 50 ml of 0.235 M NaCl solution is diluted to 200.0 ml what is the concentration of the diluted solution

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This is a straightforward dilution calculation that can be done using the equation

$M_1V_1=M_2V_2$

where M₁ and M₂ are the initial and final (or undiluted and diluted) molar concentrations of the solution, respectively, and V₁ and V₂ are the initial and final (or undiluted and diluted) volumes of the solution, respectively.

Here, we have the initial concentration (M₁) and the initial (V₁) and final (V₂) volumes, and we want to find the final concentration (M₂), or the concentration of the solution after dilution. So, we can rearrange our equation to solve for M₂:

$M_2=\frac{M_1V_1}{V_2}.$

Substituting in our values, we get

$\[M_2=\frac{\left ( 50 \text{ mL} \right )\left ( 0.235 \text{ M} \right )}{\left ( 200.0 \text{ mL} \right )}= 0.05875 \text{ M}\].$

So the concentration of the diluted solution is 0.05875 M. You can round that value if necessary according to the appropriate number of sig figs. Note that we don't have to convert our volumes from mL to L since their conversion factors would cancel out anyway; what's important is the ratio of the volumes, which would be the same whether they're presented in milliliters or liters.

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