Answer:
The most appropriate way to deal with the situation presented above is to acquire more space at the current office site at additional rent beforehand.
Explanation:
The Scaling of a revenue-generating business is a crucial task in which a lot of pre-planning and thinking is required.
In order to scale the business in the next year, the planning of it is to be carried out at the moment and proper necessary arrangements are ensured. These steps could be one from:
- Looking for bigger spaces for renting for a full shift of the operations
- Looking for a site office for an additional office
- Acquiring more space in the current office site.
This process would result in acquiring a bigger place beforehand but in order to mitigate the risk, try to keep the place in view by providing them a bare minimum advance for the additional units.
What is your question? I’ll try my best to help
1. go back to the feedback you submitted
2.Locate the order, and then click remove
3.select a reason for the removal and click to remove the feedback button.
(But why would you write a rude comment in the first place to begin with?)
The simulation, player 2 will always play according to the same strategy.
Method getPlayer2Move below is completed by assigning the correct value to result to be returned.
Explanation:
- You will write method getPlayer2Move, which returns the number of coins that player 2 will spend in a given round of the game. In the first round of the game, the parameter round has the value 1, in the second round of the game, it has the value 2, and so on.
#include <bits/stdc++.h>
using namespace std;
bool getplayer2move(int x, int y, int n)
{
int dp[n + 1];
dp[0] = false;
dp[1] = true;
for (int i = 2; i <= n; i++) {
if (i - 1 >= 0 and !dp[i - 1])
dp[i] = true;
else if (i - x >= 0 and !dp[i - x])
dp[i] = true;
else if (i - y >= 0 and !dp[i - y])
dp[i] = true;
else
dp[i] = false;
}
return dp[n];
}
int main()
{
int x = 3, y = 4, n = 5;
if (findWinner(x, y, n))
cout << 'A';
else
cout << 'B';
return 0;
}
