A mineral is a naturally occurring solid with a regular, repeating structure. true or false

Please help brainiest is award.

sineoko [7]

Answer:

7688

Explanation:

3 0

3 years ago

HELP ME PLS I NEED HELP I HAVE 5MINS

Leviafan [203]

Answer:

K

Explanation:

Since the blood moves from the body to the right atrium to the right ventricle

3 0

3 years ago

The density of a 3.37M MgCl2 (FW = 95.21) is 1.25 g/mL. Calulate the molality, mass/mass percent, and mass/volume percent. So fa

Dafna1 [17]

Answer : The molality, mass/mass percent, and mass/volume percent are, 0.0381 mole/Kg, 25.67 % and 32.086 % respectively.

Solution : Given,

Density of solution = 1.25 g/ml

Molar mass of $MgCl_2$ (solute) = 95.21 g/mole

3.37 M magnesium chloride means that 3.37 gram of magnesium chloride is present in 1 liter of solution.

The volume of solution = 1 L = 1000 ml

Mass of $MgCl_2$ (solute) = 3.37 g

First we have to calculate the mass of solute.

$\text{Mass of }MgCl_2=\text{Moles of }MgCl_2\times \text{Molar mass of }MgCl_2$

$\text{Mass of }MgCl_2=3.37mole\times 95.21g/mole=320.86g$

Now we have to calculate the mass of solution.

$\text{Mass of solution}=\text{Density of solution}\times \text{Volume of solution}=1.25g/ml\times 1000ml=1250g$

Mass of solvent = Mass of solution - Mass of solute = 1250 - 320.86 = 929.14 g

Now we have to calculate the molality of the solution.

$Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}=\frac{3.37g\times 1000}{95.21g/mole\times 929.14g}=0.0381mole/Kg$

The molality of the solution is, 0.0381 mole/Kg.

Now we have to calculate the mass/mass percent.

$\text{Mass by mass percent}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100=\frac{320.86}{1250}\times 100=25.67\%$

The mass/mass percent is, 25.67 %

Now we have to calculate the mass/volume percent.

$\text{Mass by volume percent}=\frac{\text{Mass of solute}}{\text{Volume of solution}}\times 100=\frac{320.86}{1000}\times 100=32.086\%$

The mass/volume percent is, 32.086 %

Therefore, the molality, mass/mass percent, and mass/volume percent are, 0.0381 mole/Kg, 25.67 % and 32.086 % respectively.

8 0

3 years ago

How many grams of FeCo3 will be produced from 57.2g FeCl2

Evgesh-ka [11]

Answer:

287.30 g of FeCO₃

Solution:

The Balance Chemical Equation is as follow,

FeCl₂ + Na₂CO₃ → FeCO₃ + 2 NaCl

Step 1: Calculate Mass of FeCl₂ as,

Molarity = Moles ÷ Volume

Solving for Moles,

Moles = Molarity × Volume

Putting Values,

Moles = 2 mol.L⁻¹ × 1.24 L

Moles = 2.48 mol

Also,

Moles = Mass ÷ M.Mass

Solving for Mass,

Mass = Moles × M.Mass

Putting Values,

Mass = 2.48 mol × 126.75 g.mol⁻¹

Mass = 314.34 g of FeCl₂

Step 2: Calculate Mass of FeCO₃ formed as,

According to equation,

126.75 g (1 mole) FeCl₂ produces = 115.85 g (1 mole) FeCO₃

So,

314.34 g of FeCl₂ will produce = X g of FeCO₃

Solving for X,

X = (314.34 g × 115.85 g) ÷ 126.75 g

X = 287.30 g of FeCO₃

<h2>brainlyest pleas</h2>

4 0

2 years ago

What is the average atomic mass!?

Agata [3.3K]

Answer:

he average atomic mass of an element is the sum of the masses of its isotopes, each multiplied by its natural abundance

6 0

4 years ago