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3 years ago

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What is the rate law for the uncatalyzed reaction?

2 answers:

elena55 [62]3 years ago

4 0

What is the rate law for the uncatalyzed reaction?

Metals often form several cations with different charges. Cerium, for example, forms and ions, and thallium forms and ions. Cerium and thallium ions react as follows:

2Ce^4+(aq) + Tl^+(aq) ---> 2Ce^3+(aq)+Tl^3+(aq)

This reaction is very slow and is thought to occur in a single elementary step. The reaction is catalyzed by the addition of Mn^2+ according to the following mechanism:

Ce^4+(aq)+Mn^2+(aq) ---> Ce^3+(aq)+Mn^3+(aq)

Ce^4+(aq)+Mn^3+(aq) ---> Ce^3+ (aq) + Mn^4+ (aq)

Mn^4+(aq) + Tl^+(aq) ---> Mn^2+(aq) + Tl^3+(aq)

If the uncatalyzed reaction occurs in a single elementary step, why is it a slow reaction?

1)The probability of an effective three-particle collision is low.

2) The transition state is low in energy.

3) The reaction requires the collision of three particles with the correct energy and orientation.

4) All reactions that occur in one step are slow.

The catalyzed reaction is first order in [Ce^4+] and first order in [Mn^2+]. Which of the steps in the catalyzed mechanism is rate determining?

Based on their available oxidation states, rank the following metals on their ability to catalyze this and other oxidation-reduction reactions.

Rank from best to worst catalyst.

Vanadium, titanium, manganese

murzikaleks [220]3 years ago

3 0

Answer:

For the speed of a reaction it can only be determined through experiments.

Explanation:

There are several experiments to determine the speed law. One of them is modifying the concentration of reagents and calculating this effect on the production speed of the products. By doing this, the order of said reaction can be calculated for the modified reagent. By determining the order of the reaction, the velocity law of the reaction can be calculated.

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What is the dependent and independent variable

sukhopar [10]

An independent variable is the variable changed or controlled in a scientific experiment to test the effects on the dependent variable. A dependent variable is the variable being tested and measured in a scientific experiment.

5 0

2 years ago

when carbon is burned in the air, it reacts with oxygen to form carbon dioxide. when 22.8 g of carbon were burned in the presenc

OverLord2011 [107]

Answer:

So there is83.6g CO2 produced

Explanation:

Burning carbon with air has the following equation

C + O2 → CO2

For 1 mol Carbon, we have 1 mol O2 and 1 mol CO2

Step 2: Calculating moles

mole C = 22.8g / 12g/mole

Mole C = 1.9 mole

1.9 mole C will completely react

Since for each mole C there is 1 mole O2 and 1 mole CO2

This means there will also react 1.9 mole of 02, to be formed 1.9 mole of CO2

mole CO2 = mass CO2 / Molar mass CO2

mass CO2 = 1.9 mole CO2 * 44g/mole =<u>83.6g CO2</u>

In this reaction 18.2 g of O2 remained unreacted

we can control this: 79g - 18.2 g = 60.8g

1.9 mole * 32g/mol = 60.8g

So there is83.6g CO2 produced

4 0

3 years ago

A change in matter that produces one or more new substances is a(n)

lukranit [14]

You could use another word for change can be variable witch means change and if you times the one two more times then you would get four because two time two would be four and times the one would be four.

6 0

3 years ago

What is the mass of 0.50 mole of copper?<br> 63.5 grams<br> O 32 grams<br> 3.2 grams<br> 2.18 grams

Amanda [17]

Answer:

32 g Cu

Explanation:

1 mol Cu -> 63.5 g

0.5 mol Cu ->x

x=(0.5 mol *63.5 g)/1 mol x= 32 g Cu

3 0

2 years ago

The following three equations represent reactions done in this lab exercise. Classify each reaction by their type. Note there ma

gulaghasi [49]

Answer: 1. $Cu(s)+4HNO_3(aq)rightarrow Cu(NO_3)_2(aq)+2NO_2(g)+2H_2O(l)$ : oxidation reduction

2. $Cu(NO_3)_2(aq)+2NaOH(aq)\rightarrow Cu(OH)_2(s)+2NaNO_3(aq)$ : precipitation

3. $CuO(s)+2HCl(aq)\rightarrow CuCl_2(aq)+H_2O(l)$ : Double displacement

Explanation:

Oxidation-reduction reaction or redox reaction is defined as the reaction in which oxidation and reduction reactions occur simultaneously.

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases.Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.

$Cu(s)+4HNO_3(aq)rightarrow Cu(NO_3)_2(aq)+2NO_2(g)+2H_2O(l)$

Double displacement reaction is defined as the reaction where exchange of ions takes place. Double displacement reaction in which one of the product remain in solid form are represented by (s) after their chemical formulas. Such double displacement reaction are called as precipitation reaction.

$Cu(NO_3)_2(aq)+2NaOH(aq)\rightarrow Cu(OH)_2(s)+2NaNO_3(aq)$

Double displacement reaction is defined as the reaction where exchange of ions takes place.

$CuO(s)+2HCl(aq)\rightarrow CuCl_2(aq)+H_2O(l)$

Single displacement reaction is defined as the reaction where more reactive element displaces a less reactive element from its chemical reaction.

Decomposition reaction is defined as the reaction where a single substance breaks down into two or more simpler substances.

Synthesis/Combination reaction is defined as the reaction where substances combine in their elemental state to form a single compound.

6 0

3 years ago