Answer:
= 29.64 g NaNO3
Explanation:
Molarity is given by the formula;
Molarity = Moles/Volume in liters
Therefore;
Number of moles = Molarity × Volume in liters
= 1.55 M × 0.225 L
= 0.34875 moles NaNO3
Thus; 0.34875 moles of NaNO3 is needed equivalent to;
= 0.34875 moles × 84.99 g/mol
= 29.64 g
Answer:
A & B
Explanation:
Noble Gases are the least reactive as they have a full valence shell (and are stable)
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Solution :
We know that :
and 
Then, 
..................(1)
Where,
= amount of solvent (in kg)
= amount of solute (in kg)
= molar mass of solute (g/mole)
= molality of solution (mole/kg)
Given :
= 
, 
= 0.250 kg, = 24.3 g
Then putting this values in the equation is (1),
g/mole
So, the molar mass of the unknown compound is 158.49 g/mole.
Answer:
The concentration would be 0.76 mol/L.
The most common way to solve this problem is to use the formula
c1V1=c2V2
In your problem,
c1 = 4.2 mol/L; V1 = 45.0 mL
c2 = ?; V2 = 250 mL
c2=c1×V1V2 = 4.2 mol/L × 45.0mL250mL = 0.76 mol/L
This makes sense. You are increasing the volume by a factor of about 6, so the concentration should be about ¹/₆ of the original (¹/₆ × 4.2 = 0.7).
Explanation:
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