All categories

3 years ago

We have 42 oranges in 7 bags how many oranges are in each bag?

Mathematics

2 answers:

lutik1710 [3]3 years ago

6 0

There are 6 oranges per bag :3

EastWind [94]3 years ago

4 0

The answer is six. Take 42 divided by 7

You might be interested in

Need help on the last problem

mylen [45]

no. of right answers = 60

no. of wrong answers = 40

6 0

3 years ago

a state charges an 8.5% sales tax and a 10% excise tax on gasoline. he purchased $25 of gasoline before tax. How should he find

Mama L [17]

Answer:

The total money spend on total tax of purchase is $4.625

Step-by-step explanation:

Given as :

The percentage of sales tax applied on gasoline purchase = 8.5%

The percentage of excise tax applied on gasoline purchase = 10%

The price of gasoline before tax = $25

Let The total money on total tax of purchase = $x

Now, Total percentage of tax = sales tax percentage + excise tax percentage

i.e Total percentage of tax = 8.5% + 10%

Or, Total percentage of tax = 18.5%

Again

total money on total tax of purchase = $25 of total total tax percentage

Or, x = $25 × 18.5%

Or, x = $25 × $\dfrac{18.5}{100}$

Or, x = $25 × 0.185

∴ x = $4.625

So,The total money on total tax of purchase = x = $4.625

Hence,The total money spend on total tax of purchase is $4.625 Answer

4 0

3 years ago

Pls help with 29 and 19

Phoenix [80]

You should have written like this
1 hour /16 = x hour /100
x=100/16=25/4=6.25
but it asks how many hours after first hour
6.25-1=5.25

5 0

3 years ago

Please answer this correctly

tekilochka [14]

Take the coordinates
Ex.
(-5,-1) and count it on the chart
The first number is your x value and ur second number is ur y
Y= up and down
X= side to side

3 0

4 years ago

1+secA/sec A = sin^2 A / 1-cos A

Fofino [41]

Answer: see proof below

Step-by-step explanation:

$\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}$

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

Proof LHS → RHS

$\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}$

$\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}$

$\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}$

$\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}$

$\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}$

$\text{LHS = RHS:}\quad \dfrac{\sin^2 A}{1-\cos A}=\dfrac{\sin^2 A}{1-\cos A}\quad \checkmark$

3 0

3 years ago