Consider the chemical equation. CuCl2 + 2NaNO3 mc023-1.jpg Cu(NO3)2 + 2NaCl What is the percent yield of NaCl if 31.0 g of CuCl2
2 answers:
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Answer:
The reactions free energy
Explanation:
From the question we are told that
The pressure of (NO) is
The pressure of (Cl) gas is
The pressure of nitrosly chloride (NOCl) is
The reaction is
⇆
From the reaction we can mathematically evaluate the (Standard state free energy ) as
The Standard state free energy for NO is constant with a value
The Standard state free energy for is constant with a value
The Standard state free energy for is constant with a value
Now substituting this into the equation
The pressure constant is evaluated as
Substituting values
The free energy for this reaction is evaluated as
Where R is gas constant with a value of
T is temperature in K with a given value of
Substituting value
Answer: Heat of the solution = mass water × specific heat water × change in temperature
mass water = 260ml (1.00g/ml ) = 260g
specific heat of water = c(water) = 4.184J/ g°C
Heat change of water = final temperature - initial temperature
= 26.5 - 21.2
= 5.3 °C
H = 260 g ( 4.184J/g°C ) (5.3°C) = 5765J
Molar heat =
= 16473J/mol
Explanation: finding molar heat requires first to look at specific heat of water and the change of water temperature
Answer: 83%
Explanation:
The detailed solution is shown in the image attached. First we must work out the balanced reaction equation because accurate solution of the problem must be based on the stoichiometry of the reaction. From the given concentration and volume of reactants, we calculate the amount of substance reacted hence identify the limiting reactant. Lastly we use simple proportion to obtain the theoretical yield of the precipitate. This is now used to calculate the actual yield as shown in the solution attached.
