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Answer:
The molar mass of the compound given is 182.182 g/mol.
Explanation:
To calculate the molar mass of the compound, we must multiply the number of moles of each element by the the individual molar mass of each element and add them together.
Let's start with Calcium. The molar mass of Calcium is 40.078. In this compound, we have three moles of Calcium, so we should multiply this number by 3.
40.078 g/mol * 3 mol = 120.234 g
Now, let's do the same for Phosphorus.
30.974 g/mol * 2 g/mol = 61.948 g
To find the molar mass of the entire compound, we should add these two values together.
120.234 g + 61.948 g = 182.182 g
Therefore, the correct answer is 182.182 g/mol.
Hope this helps!
Answer: the correct option is (C).
Explanation:
Covalent compounds have lower melting and boiling points due to presence of weak inter-molecular forces by which molecules are weakly associated to each other. Hence, melting and boiling of covalent compounds occurs at low temperatures.
Usually, Covalents compounds have following properties:
- They are brittle solids
- They do not conduct electricity
- They do not have rigid crystal structure.
- They exist in all states: solids, liquids and gases.
Answer:
3.93 mol
Explanation:
The balanced equation is given as;
2 Fe₂S₃+ 9 O₂ --> 2 Fe₂O₃ + 6 SO₂
From the reaction;
2 mol of Fe₂S₃ reacts with 9 mol of O₂ to form 6 mol of 6 SO₂
This means;
1 mol of Fe₂S₃ requires 9/2 mol of O₂
Also,
1 mol of O₂ requires 1/9 mol of Fe₂S₃
In the question, we have;
1.31 moles of Fe2S3 and 22.8 moles of O2
The limiting reactant which determine how much of the product formed is; Fe₂S₃ because O₂ is in excess.
The relationship between Fe₂S₃ and SO₂ is;
2 mol Fe₂S₃ produces 6 mol of SO₂
1.31 mol of Fe₂S₃ would produce x mol ?
2 = 6
1.31 = x
x = 6 * 1.31 / 2 = 3.93 mol
