Answer:
6.18 g
Explanation:
We know we will need a balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.
: 41.99
Na₂SiO₃ + 8HF ⟶ 2NaF + H₂SiF₆ + 3H₂O
<em>n</em>/mol: 0.58
1. Use the molar ratio of NaF:HF to calculate the moles of NaF.

2. Use the molar mass of NaF to calculate the mass of NaF.

Photosynthsis is a process that a plant goes through to turn sugars into energy
Answer:
This is the conversion factor, we have to use:
44 g / 1mol
Explanation:
The reaction for the methane combustion is:
CH₄ + 2O₂ → CO₂ + 2H₂O
First of all we use this conversion factor to determine the moles of methane, we used.
50.6 g . 1 mol / 16 g = 3.16 mol
So ratio is 1:1, then 3.16 mol of methane will produce 3.16 moles of CO₂
To calculate the grams of produced dioxide:
3.16 mol . 44 g / 1mol = 139.04 g
The answer is a Roman numeral.
Ex:
1: I
2: II
3: III
4: IV
5: V
6: VI
7: VII
8: VIII
9: IX
10: X
What is the specific heat of aluminum?
The specific heat of aluminum is 0.90J/g°C.
Given:
Heat absorbs = 677 J
Mass of the substance = 10 g
Initial temperature = 50°C
Final temperature = 125°C
Formula used:
Q = m x c x ΔT
which can also be written as,
Q = m x c x (
-
)
where,
Q = heat absorbs
m = mass of a substance
c = heat capacity of aluminum
= Final temperature
= Initial temperature
Now, put all the values in the formula given above to get the specific heat of aluminum,
677g = (10g) x c x (125 - 50)°C
c = 0.9026 J/g°C
c = 0.90 J/g°C
Learn more about the specific heat of aluminum here,
brainly.com/question/13696634
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