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DENIUS [597]
3 years ago
7

Use the drop-down menus to complete the sentence below. A is an organism that may be eaten by a .

Biology
3 answers:
Free_Kalibri [48]3 years ago
5 0
Maybe include a picture of all the options or type out the options so someone can help
a_sh-v [17]3 years ago
4 0

Answer:

what are the drop down menus

Explanation:

lyra2 years ago
0 0

Answer:
a PRIMARY CONSUMER is an organism that may be eaten by a SECONDARY consumer
for short
1. PRIMARY CONSUMER
2. SECONDARY CONSUMER

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An organism’s traits are determined by the specific combination of inherited _____.
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Answer:

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Explanation:

Genes are present on DNA that are inherited from parents to their offspring. Genes may be defined as the segment of DNA that ultimately form a particular protein product.

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Thus, the correct answer is option (2).

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Which is a homologous chromosome pair?
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Answer: Homologous chromosomes are the pairs of chromosomes that having same gene sequence, equal length of arms and centromere location. Homologous chromosomes have two homolog one come from male parent and other come from female parent.

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3 years ago
Why is the weight of an object more on Earth than on the Moon?
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7 0
3 years ago
What is the magnitude of the force exerted by the biceps fbiceps? What is the magnitude of the force exerted by the elbow felbow
Slav-nsk [51]

Answer:

<u> </u><u>The magnitude of the force exerted by the biceps </u>f_b_i_c_e_p_s<u> is 218.38N</u>

<u>The magnitude of the force exerted by the elbow </u>f_e_l_b_o_w<u> is 194.37N</u>

Explanation:

Firstly , lets calculate the magnitude of force exerted by biceps f_b_i_c_e_p_s -

Mass of the forearm=

m_f=1.50kg

Mass of the ball =

m_b_a_l_l=950g

   = 0.950kg

so, weight of the forearm=

w_f=m_f g

weight of the ball=

w_b_a_l_l=m_b_a_l_l g

Now , balancing torque about the elbow , we have-

F_b_i_c_e_p_s\times d_b_i_c_e_p_s= w_f\times\frac{d_b_a_l_l}{2} + w_b_a_l_l\times d_b_a_l_l

(here , distance of the bicep is 2.50cm = 0.025m and distance of the ball is 36cm= 0.36m)

Now putting the given values in the formula -

F_b_i_c_e_p_s\times 0.025= 0.95\times9.8\times\frac{0.36}{2} +1.50\times 0.36

F_b_i_c_e_p_s=218.38N

Now, lets calculate the force exerted by elbow F_e_l_b_o_w -

Balancing the vertical forces

F_b_i_c_e_p_s=F_e_l_b_o_w+w_f+w_b_a_l_l

F_e_l_b_o_w = 218.38-(1.00\times9.8)-(0.95\times9.8)

F_e_l_b_o_w=194.37N

8 0
3 years ago
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