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3 years ago

In how many ways 5 people can sit on 5 chairs on a podium

Mathematics

2 answers:

pickupchik [31]3 years ago

8 0

Answer:

The orientation doesn't depend on their seat or anyone else's orientation. So there would be 5! ways of arranging 5 people and for each of those 5 people, there would be 4 orientations. This means that there would be 4^5 ways of orienting everyone.

Step-by-step explanation:

Vikki [24]3 years ago

4 0

Answer:

120 people

Step-by-step explanation:

The number of people as well as the number of chairs is 5

so that means there are exactly 120 ways in which they can be seated.

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HELP DUE AT 8:30 I NEED To Do DIS

lbvjy [14]

Answer:

Step-by-step explanation:

5 0

2 years ago

Can some one help me asap

zavuch27 [327]

It'd be easier to do #18 if y ou were to break it up:

14* (first term + 14th term)
Sum from n=1 to 14 of n = S = ---------------------------------
14 2

14(1+14)
= ---------------- = 7(15) = 105
2

The sum of twice that is 210. The sum of "1 from n=1 to n=14" is just 14.

The final sum is 210 + 14 = 224 (answer)

4 0

3 years ago

Solve each inequality, and then drag the correct solution graph to the inequality.

Nesterboy [21]

The correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

(NOTE: The graphs are labelled A, B and C from left to right)

For the first inequality,

$4(9x-18)>3(8x+12)$

First, clear the brackets,

$36x-72>24x+36$

Then, collect like terms

$36x-24x>36+72\\12x >108$

Now divide both sides by 12

$\frac{12x}{12} > \frac{108}{12}$

∴ $x > 9$

For the second inequality

$-\frac{1}{3}(12x+6) \geq -2x +14$

First, clear the fraction by multiplying both sides by 3

$3 \times[-\frac{1}{3}(12x+6)] \geq3 \times( -2x +14)$

$-1(12x+6) \geq -6x +42$

Now, open the bracket

$-12x-6 \geq -6x +42$

Collect like terms

$-6 -42\geq -6x +12x$

$-48\geq 6x$

Divide both sides by 6

$\frac{-48}{6} \geq \frac{6x}{6}$

$-8\geq x$

∴ $x\leq -8$

For the third inequality,

$1.6(x+8)\geq 38.4$

First, clear the brackets

$1.6x + 12.8\geq 38.4$

Collect likes terms

$1.6x \geq 38.4-12.8$

$1.6x \geq 25.6$

Divide both sides by 1.6

$\frac{1.6x}{1.6}\geq \frac{25.6}{1.6}$

∴ $x \geq 16$

Let the graphs be A, B and C from left to right

The first graph (A) shows $x\leq -8$ and this matches the 2nd inequality

The second graph (B) shows $x \geq 16$ and this matches the 3rd inequality

The third graph (C) shows $x > 9$ and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

Learn more here: brainly.com/question/17448505

8 0

2 years ago

Suppose that the revenue function for a certain product is given by R(x) = 17(2x + 1)−1 + 34x − 17 where x is in thousands of un

REY [17]

Answer:

Step-by-step explanation:

Given that:

R(x) = $\frac{17}{2x+1}$ + 34x − 17

As we know that derivative of revenue function is marginal revenue function .

We will use following rules of derivative

=> dR/ dx = $\frac{-17*2}{(2x+1)^{2} } + 34$

=> R' (x) = $\frac{-34}{(2x+1)^{2} } + 34$

=> R '(2000) = $\frac{-34}{(2*2000+1)^{2} } + 34$ = 34

The revenue when 2000 units are sold is:

R(2000) = $\frac{17}{2*2000+1}$ + 34*2000 − 17 = $69,783

3 0

3 years ago

13-5m=4-6m show work please

Vesna [10]

First subtract 4 from both sides
$13 - 4 - 5m = - 6m$

then simplify
$9 - 5m = - 6m$

add -5 to both sides
$9 = - m$

since a variable shouldn't be negative the answer should be
$m = - 9$

(I prefer having the variable on the left side)

4 0

3 years ago