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pychu [463]
2 years ago
14

Question 3 of 10

Chemistry
1 answer:
Nookie1986 [14]2 years ago
7 0

Answer:

A change in a substance where one or more new substances form

Explanation:

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Which particle changes to create an isotope of an atom? <br> A.proton<br> B.neutron<br> C.electron
Dovator [93]

Answer:

A

Explanation:

proton

5 0
3 years ago
. What is the mass, in grams, of a sample of 7.83 × 1024 atoms of helium (He)?
erica [24]
Moles He = 7.83 x 10^24 / 6.02 x 10^23 =13.0 

<span>mass He = 13.0 mol x 4.00 g/mol = 52.0 g</span>
6 0
3 years ago
The atomic number of polassium and
never [62]

Explanation:

Atomic radius decreases from left to right in a period.

Therefore Calcium would have a smaller atomic size.

6 0
3 years ago
How many grams of a stock solution that is 92.5 percent H2SO4 by mass would be needed to make 250 grams of a 35.0 percent by mas
IrinaVladis [17]

94.6 g.  You must use 94.6 g of 92.5 % H_2SO_4 to make 250 g of 35.0 % H_2SO_4.

We can use a version of the <em>dilution formula</em>

<em>m</em>_1<em>C</em>_1 = <em>m</em>_2<em>C</em>_2

where

<em>m</em> represents the mass and

<em>C</em> represents the percent concentrations

We can rearrange the formula to get

<em>m</em>_2= <em>m</em>_1 × (<em>C</em>_1/<em>C</em>_2)

<em>m</em>_1 = 250 g; <em>C</em>_1 = 35.0 %

<em>m</em>_2 = ?; _____<em>C</em>_2 = 92.5 %

∴ <em>m</em>_2 = 250 g × (35.0 %/92.5 %) = 94.6 g

4 0
3 years ago
What will be the volume occupied by 2.5 moles of nitrogen gas exerting 1.75 atm of pressure at 475K?
Marina86 [1]

Answer:

THE VOLUME OF THE NITROGEN GAS AT 2.5  MOLES , 1.75 ATM AND 475 K IS 55.64 L

Explanation:

Using the ideal gas equation

PV = nRT

P = 1.75 atm

n = 2.5 moles

T = 475 K

R = 0.082 L atm/mol K

V = unknown

Substituting the variables into the equation we have:

V = nRT / P

V = 2.5 * 0.082 * 475 / 1.75

V = 97.375 / 1.75

V = 55.64 L

The volume of the 2.5 moles of nitrogen gas exerted by 1.75 atm at 475 K is 55.64 L

6 0
3 years ago
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