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motikmotik
3 years ago
11

An initial mixture of nitrogen gas and hydrogen gas is reacted in a rigid container at a certain temperature by the reaction At

equilibrium,the concentrations are [H2] 5.0 M,[N 2] 8.0 M, and [NH3] 4.0 M. What were the concentrations of nitrogen gas and hydrogen gas that were reacted initially?
Chemistry
2 answers:
anygoal [31]3 years ago
8 0

Answer: [N2]₀ = 10M and [H2]₀ = 11M

Explanation: To calculate the initial concentration, you would have to set up an ICE table, which is an organized way of tracking known quantities or the ones you want to find. ICE stands for:

I is initial amount;

C is change in concentration;

E is for equilibrium concentration;

For the mixture,

       N2                       3H2                2NH3

I      [N2]₀                     [H2]₀                  0

C     - x                          -3x                 +2x

E     [N2]₀ - x =8      [H2]₀ - 3x =5       2x =4

With the product, we can find "x":

2x=4

x=2M

With x=2, find the concentrations:

[N2]₀ - x = 8

[N2]₀ = 10M

[H2]₀ - 3x = 5

[H2]₀ = 11M

The initial concentrations of nitrogen gas [N2] is 10.0 M and of hydrogen gas [H2] is 11.0 M.

bezimeni [28]3 years ago
8 0

Answer:

Conc. Of H =11

Conc. Of N =10

Explanation:

Provided that the equation for thr reaction is

3H2 + N2 <---> 2NH3

Then

I = 5.0+3x 8.0+x 0

C = -3x -x +2x

E = 5.0 8.0 4.0

But

x=2

So

H2=5.0+3x

5+6=11

N2= 8.0+x

N2=10

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klio [65]

Answer:

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Explanation:

Given that:

mass of caffeine in 100 mL of water =  600 mg

Volume of the water = 100 mL

Partition co-efficient (K) = 4.6

mass of caffeine extracted = ??? (unknown)

The portion of the DCM = 60 mL

Partial co-efficient (K) = \frac{C_1}{C_2}

where; C_1= solubility of compound in the organic solvent and C_2 = solubility in aqueous water.

So; we can represent our data as:

K=(\frac{A_{(g)}}{60mL} ) ÷ (\frac{B_{(mg)}}{100mL} )

Since one part of the portion is A and the other part is B

A+B = 60 mL

A+B = 0.60

A= 0.60 - B

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4.6 = \frac{(\frac{0.6-B(mg)}{60mL} )}{(\frac{B_{(mg)}}{100mL})}

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2.76 + B = 0.6

3.76 B = 0.6

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3 years ago
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kolezko [41]

Answer:

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san4es73 [151]

Answer : The moles of H_2SO_4 are, 2.125 mole.

Explanation : Given,

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If two gases with pressures of 2 atm and 3 atm are mixed at a constant temperature, what will the total pressure be?
slamgirl [31]
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