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OleMash [197]
3 years ago
15

When h+ forms a bottle of h2o to form the hydronium ion h3o plus this bond is called a coordinate covalent bond because?

Chemistry
2 answers:
nalin [4]3 years ago
4 0
This is called as such because the proton or H+ has taken on both lone electron pairs on the oxygen in the water molecule. As such it is s coordinate covalent bond.
dybincka [34]3 years ago
3 0

Answer:

The bond formed between H^{+} ion and water molecule is a type of coordinate covalent bond where both the bonding electrons are shared from the oxygen atom of the H_{2}O molecule.

Explanation:

Actually, the coordinate covalent bonds are such bonds which are formed when only one atom shares both the bonding electrons with another atom to form a bond.

Here, the hydrogen ion has only one proton and so it can not share electrons for bond formation. Hence, it accepts one lone pair of electrons from the oxygen atom of the water molecule and thus forms a coordinate covalent bond.

The coordinate covalent bonding between H^{+} ion and water molecule is shown as:

<h2>H^{+}(aq) + H_{2}O (l)-> H_{3}O^{+}(aq)</h2>

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A container of hydrogen gas has the same temperature as a container of oxygen gas. The gas atoms having the greater average kine
user100 [1]

Answer:

hope this helps

Explanation:

The atoms of hydrogen have smaller mass than oxygen. Thus their speeds have to higher in order to produce the same average kinetic energies.

4 0
2 years ago
Y'all what about this one
Virty [35]

Answer:

A=8, B=7,C=N

D=26, E=30, F =Fe

4 0
3 years ago
How much heat is added if .0948g of water is increased in temperature by .728 degrees C?
Verdich [7]

Answer:

0.289J of heat are added

Explanation:

We can relate the change in heat of a substance with its increasing in temperature using the equation:

q = m*ΔT*S

<em>Where Q is change in heat</em>

<em>m is mass of substance (In this case, 0.0948g of water)</em>

<em>ΔT = 0.728°C</em>

<em>S is specific heat (For water, 4.184J/g°C)</em>

Replacing:

q = 0.0948g*0.728°C*4.184J/g°C

q = 0.289J of heat are added

5 0
3 years ago
Lily is doing a science experiment with a substance in a sealed jar. At first, the substance's molecules are moving around each
Alex

The molecules will be more separated, and will have least amount of intermolecular force of attraction.

<h3><u>Explanation:</u></h3>

The molecules inside the jar of Lilly are moving around each other. This means the state of the matter present inside the jar is liquid. As Lily gives more energy inside the jar , the molecules inside the jar will get more separated as the kinetic energy of the molecules increase and the intermolecular force of attraction decreases as well as the intermolecular separation or distance increase. As the energy is continued to be supplied from outside, there will be a time when this liquid will reaches boiling point and will start to change into gas. After this point the intermolecular force of attraction will be least among molecules and their separation will be maximum.

6 0
3 years ago
The colligative molality of an unknown aqueous solution is 1.56 m.
yawa3891 [41]

Answer:

Vapor pressure of solution = 17.02 Torr

T° of boiling point for the solution is 100.79°C

T° of freezing point for the solution is -2.9°C

Explanation:

Let's state the colligative properties with their formulas

- <u>Vapor pressure lowering</u>

ΔP = P° . Xm . i

- <u>Boiling point elevation</u>

ΔT = Kb . m . i

-<u> Freezing point depressión</u>

ΔT = Kf . m . i

ΔP = Vapor pressure pure solvent (P°) - Vapor pressure solution

ΔT = T° boling solution - T° boiling pure solvent

ΔT = T° freezing pure solvent - T° freezing solution

i represents the Van't Hoff factor (ions dissolved in the solution). If we assume that the solute is non-volatile and the solution is ideal i = 1

Kf and Kb are cryoscopic and ebulloscopic constant, they are  specific to each solvent.

Vapor pressure works with mole fraction (Xm) and the only data we have is molality, so we consider 1.56 moles of solute and 1000 g of solvent mass.

Moles of solvent → solvent mass / molar mass of solvent

Moles of solvent → 1000 g / 18 g/mol = 55.5 moles

Mole fraction is moles of solute / Total moles (mol st + mol sv)

Mole fraction: 1.56 / (1.56 + 55.5) = 0.027

- Vapor pressure lowering

ΔP = P° . Xm . i

17.5 Torr - Vapor pressure of solution = 17.5 Torr . 0.027 . 1

Vapor pressure of solution = - (17.5 Torr . 0.027 . 1 - 17.5 Torr)

Vapor pressure of solution = 17.02 Torr

- Boiling point elevation

ΔT = Kb . m . i

T° boiling solution - 100° = 0.512 °C/ m . 1.56 m . 1

T°boiling solution = 0.512 °C/ m . 1.56 m . 1 + 100°C

T°boiling solution = 100.79°C

- Freezing point depression

ΔT = Kf . m . i

0°C - T° freezing solution = 1.86 °C/m . 1.56 m . 1

T° freezing solution = - (1.86 °C/m . 1.56 m)

T° freezing solution = -2.9°C

3 0
3 years ago
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